What will be the strain induced in a steel rod of length 200 mm that is subjected to a tensile load of 100 kN when the extension of the rod is equal to 0.4 mm ?
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- A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.2. The manufactured wood beam carries the concentrated loads shown. What is the maximum safe value of P if the working stress in shear is 6 MPa? 20 mm 80 mm |3P 2 m 2 m 70 mm B 160 mm -- NA I = 15.52 × 106 mmª 1.0 m 1.0 m 20 mmDefine the below ? Lateral strain is considered – Skempton–Bjerrum method
- A steel tube with 3cm outside diameter, 0.25cm thick, and 4m long is covered and lined throughout with copper tubes 0.20cm thick. The three tubes are joined together at their ends. What is the maximum compressive load that can be applied to the top such that the total deformation does not exceed 0.50mm? Esteel = 200 GPa & Ecopper = 110 GPa.A 2-m long steel rod, 10-mm in diameter, is carrying a load of 20 kN. (a) what is the axial stress developed in the rod, in kN/m^2. Is the tensile or compressive? (b) compute the amount of elongation (in mm) in the steel rod caused by the applied load, (c) what will be the elongation (in mm) in the steel rod if the weight of the steel rod is included? Use density of the steel to be 7860 kg/m^3. Young's modulus of elasticity, E=200GPa. W=mg. Draw free body diagram of the steel rod.The rigid bar of negligible weight is pinned at O and attached to two vertical rods. Assuming thatthe rods were initially stress-free, what is the largest load P that can be applied without exceedingstresses of 150 MPa in the steel rod and 70 MPa in the bronze rod?
- Q2) The rigid plate ABC shown in figure 2, was positioned on top of two identical steel posts, and the aluminum post was 0.Imm shorter than the steel posts at temperature of 50 C, if the allowable compressive stress in steel is limited to 200MPa and in aluminum to 150 MPa, what is the maximum possible load P that can be supported on the rigid plate at temperature of 10'C ? steel E. 200 GR A = 1600 mar Ae1 steel T 50'd Alusinam L-250M = 200 M. Aluminum Post E= 73 GPa A = 2400 Ma = 23 K10 l 150 MP. comp Figure 2A hollow cylinder with an OD of 100mm and an ID of 30mm, supports a load of 100kN. What is the compressive stress in MPa?.............I know stress=p/a , but I am not sure how to find the height in order to calculate the area or if there would be another way of doing it ?The working load P on the propped cantilever shown are each 150 kN. If the yield stress of mild steel is 300 MPa, determine the plastic section modulus in cubic millimeters, using a load factor of 1.75 against collapse. (express your response this way, x,xxX,XXX.X). Pu Pu 1.1 2m B A 2m 2m
- What maximum load P can be applied without exceeding an allowable stress of 70 MPa for aluminum or 120 MPa for steel? Can a larger load P be carried if the length of the aluminum rod is changed. the length of the steel portion being kept the same? If so, determine this lengthTwo wooden boards are joined by cutting and gluing them together along the plane shownin the illustration. The boards have cross-sectional dimensions of 3.5” by ¾” and are subjectedto an axial tension, P, of 1870 lb.a) Determine the normal and shear stresses acting on the glued joint if = 20o.b) For what joint angle, , will the shear stress on the glued joint be equal (in magnitude) totwice the normal stress on the joint?The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the loadP 20 KN is applied. 15m What is the axial deformation of stecl rod in mm?