Answered: What will be the final value in EDX…

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What will be the final value in EDX after this code executes?mov edx,1mov eax,7FFFhcmp eax,8000hjb L1mov edx,0L1:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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START: CLC MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: MOV AL, (DI) ADC (SI), AL INC SI INC DI DEC CX JNZ LOOP HLT (0300H) = 1AH, (0301H) = 2BH, (0302H) = ЗСH, (030ЗH) %3D 4DH. The result will be: Select one: a. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 66H, (0303H) = 77H b. (0300H) = 1AH, (0301H) = 2BH, (0302H) 3 ЗСH, (0303Н) %3 4DH c. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 56H, (0303H) = 87H d. None of the options given here.
3. Add B36EH with 264DH. Specify Flag status. SF=? ZF=? AF=? PF=? CF =?
def read_flights(flights_source: TextIO, routes: RouteDict) -> FlightDir: """Return the flights from flights_source, including only the ones that have an entry in routes. >>> from io import StringIO >>> flight_src = StringIO(TEST_FLIGHTS_SRC) >>> actual = read_flights(flight_src, TEST_ROUTES_DICT_FOUR_CITIES) >>> actual == TEST_FLIGHTS_DIR_FOUR_CITIES True """ flights = [] src_index = FLIGHT_DATA_INDEXES["Source airport"] dst_index = FLIGHT_DATA_INDEXES["Destination airport"] # Complete this function. for line in routes_source:
Q: Change this code from Matlab to Phython: 2 clear 3 data load ('ex2data2.txt'); x = data (:, [1, 2]) ; y = plotData (X, y): 6 hold on; xlabel ('Microchip Test l') ylabel ('Microchip Test 2') legend ('y = 1', 'y = 0') 4 data (:, 3); 8 9 %3D 10 hold off; mapFeature (X (:, 1), x (:, 2)); initial_theta = 11 X = zeros (size (X, 2), 1); 13 lambda = 1; O H N3
The memory location at address 00002001 contains the memory variable. What is the data memory variable in hexadecimal form? MEMORY O a. The memory variable data in hexadecimal form is E3. O b. The memory variable data in hexadecimal form is D3. 0 с. The memory variable data in hexadecimal form is F3. memory variable data in hexadecimal form is E4. The O d. E4 FD ED FA AE DE DATA 00002001 00002000 00001999 00001998 00001997 00001996 ADDRESS
Please describe what this testbench code is doing. You can use comments for each line if that is easier for you. This code is using Verilog. `timescale 1ns / 1ps module display_tb02(); reg [4:0] P; reg [1:0] X; wire [3:0] an; wire [0:7] led; Disp_tester uut( .P(P), .X(X), .an(an), .led(led) ); initial begin $display("\nTestbench start"); {P,X}=0; //quantity formed by concatenating....initialized to 0 #100; end always begin #10; //wait for 10 * 1ns = 10ns if ({P,X} === 'b1111111) begin #10; $display("Testbench end"); $finish; end else begin {P,X} = {P,X} + 1; $display("P,X=%0d,%0d",P,X); $display("an,led=,%b,%b",an,led); end end endmodule
What will be the final value in EDX after this code executes?mov edx,1mov eax,7FFFhcmp eax,8000hjl L1mov edx,0L1
None
#include <xc.h> void ____(void); void main (void) { TRISDbits.TRISD0 = ____;TRISDbits.TRISD1 = 0;TRISDbits.TRISD2 = ____;TRISDbits.TRISD3 = 0; ____ = 0; PORTDbits.RD0 = ____; PORTDbits.RD1 = 0; if(____ == 0)fail(); PORTDbits.RD0 = ____; PORTDbits.RD1 = 1; if(PORTDbits.RD2 == 0)fail(); ____ = 1; PORTDbits.RD1 = 0; if(____ == 0)____; PORTDbits.RD0 = ____; PORTDbits.RD1 = ____; if(PORTDbits.RD2 == ____)fail(); while(1) { PORTDbits.RD3 = 1; PORTDbits.RD4 = 0; } } void fail(void) { while(1) { PORTDbits.RD3 = ____; PORTDbits.RD4 = ____; } }
Shown below is a small Verilog snippet. Indicate what the value of maskedValue is after the always block executes. always @(-) begin originalValue- 16' HABD9; mask = 16'h5555; maskedValue = originalValue & mask; end
How will this expression be evaluated in the R Console? > (5+7)^2 O 144 072 54 O 74
HAHAAAAAAHN HNM1000 OHNM 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 27 28 30 31 32 section . data .section .text .globl _start start: pushq $4 pushq $3 call function-A addq $16, $rsp movg %rax, %rbx movq $1, rax int $0x80 .type function-A, @function function-A: pushq rbp movq rsp, rbp. subq $8, rsp movg 16(%rbp), %rbx movq 24 (rbp), rcx movg %rbx, -8(%rbp) label-A: #variable y #variable z cmpq $1, $rcx je label-B movq -8 (&rbp), rax imulg %rbx, srax movq krax, -8 (%rbp) decq rcx jmp label-A label-B: movq -8 (Srbp), rax movq rbp, rsp popq &rbp ret