What volume of carbon dioxide in liters could be generated at 0.977 atm and 399. K by the combustion of 274.62 grams of pentane (C5H12) with excess oxygen gas? C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g) (OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g") R = 0.08206L atmmol K
a) What volume of carbon dioxide in liters could be generated at 0.977 atm and 399. K by the combustion of 274.62 grams of pentane (C5H12) with excess oxygen gas?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)
(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")
R = 0.08206L atmmol K
b) What volume of carbon dioxide in liters could be generated at 0.977 atm and 431. K by the combustion of 203.62 grams of oxygen gas excess pentane gas (C5H12)?
C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)
(OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g")
R = 0.08206L atmmol K
c) What volume of water vapor gas would be produced from the combustion of 544.42 grams of propane (C3H8) with 2,581.357 grams of oxygen gas, under a pressure of 0.96 atm and a temperature of 350. degrees C? Given:
C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(g)
(OR C3 H8 ("g") + 5 O2 ("g") right arrow 3 C O2 ("g") + 4 H2O ("g")
R = 0.08206L atmmol K
d) What volume of carbon dioxide gas would be produced from the combustion of 880.57 grams of propane (C3H8) with 1,538.99 grams of oxygen gas, under a pressure of 1.012 atm and a temperature of 350. degrees C? Given:
C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(g)
(OR C3 H8 ("g") + 5 O2 ("g") right arrow 3 C O2 ("g") + 4 H2O ("g")
R = 0.08206L atmmol K
Trending now
This is a popular solution!
Step by step
Solved in 5 steps