What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 5.30 L of an HCl solution with a p of 1.90? Express your answer to two significant figures and include the appropriate units. a) ? HA Value Units

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What is the molarity of a solution in which 4.00 mol of potassium chloride (molar mass 74.55 g/mol) is dissolved in 3.00 L of solution? O 2.67 M 4.00 M 6.00 M O 1.33 M MacBook Air D00 20 F3 F10 esc F4 F5 F7 F8 F9 F6 F1 F2 @ #3 2$ % 2 3 6 8 Q W E R Y ーの

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Equal volumes of Solutions 2 and 3 were mixed in the lab. Suggest a measurement that could be made in the lab to provide evidence that a chemical reaction occurred when Solutions 2 and 3 were mixed.

A Moving to another question will save this response. uestion 4 What mass of NaCl is needed to make 20.0 mL of a 1.00 M solution? Molarity (M) = moles/Liter O 1.17 g O 1170 g O 1.00 g O 0.0200 g 2930 g Moving to another question will save this response. NOV étv

solution. You have 2.5ml of a 1mg/mL NaCl solution. You need to make 5 mL of a 0.25mg/mL HAVE (Stock solution) C₁ 1mg/mL NaCl V₁ = ? mL Please note: NEED (New solution) C₂ = 0.25mg/mL V₂ = 5mL • The needed/ new solution is more dilute (less concentrated) than the stock solution. • It does not matter how much (volume) of stock solution one has, what matters is how much is needed to make a new solution of given concentration and volume. • The units of volume and concentration on both sides of the equation must be the same. C*Vi C2 * V2 (1mg/mL) (V1mL) (0.25mg/mL) * (5mL) V1 mL (0.25mg/ml) * (5mL) = 1mg/mL 1.25 mg 1 mg/ml V₁ = 1.25mL Even though you had 2.5mL of stock solution, only 1.25mL of it is needed to make the diluted solution. • The final volume of the new solution is 5mL. You will need to add (V1-V2 = 5ml - 1.25mL) 3.75mL of diluent to the 1.25mL stock solution.

Alcoholic beverages come in many different concentrations denoted by their weight percent (w/w). If a beer is marked as 4.0%, it means there are 4.0 grams of ethanol (C2H6O) in every 100.00 grams of solution. Assuming this solution has a density of 1.00 g/mL, what is the molar concentration of this solution? Give your answer in in decimal format. When entering units, use proper abbreviated units with proper capitalization.

Calculate the volume of stock glucose solutions (2.5 % and 15%) that need to be used to prepare 800 mL of glucose solution with a concentration of 13%. In this case % refers to the grams of glucose per 100 mL of water. V1= volume of stock solution with concentration C (2.5%) V2= volume of stock solution with concentration C2 (15 %) You need to determine V, and V2 in mL

How many of the data sets listed could be used to find the number of grams of solute in solution? 34567 27 g of unknown compound in water ( Compound is Soluble) A 0.05 M MgCl2 solution x 1022 molecules of unknown compound in water A 1.2 L solution of MgCl2 with 0.05 M Mg²+ A 1.2 L solution of MgCl2 A 1.2 L solution of unknown compound with 0.05 M Cl- 15 x 1022 molecules of nonelectrolyte CH3OH in water