What volume (in ml) of 0.829 M Ca3(PO4)2 required to provide 0.0186  moles of Ca2+ ions?

16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm solution. A 25.00 cm of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(N03)2(aq) + 2H2O(1) The concentration of Ba(OH)2 in the 100.00 cm3 volumetric flask is: O 1.96 x 103 M O 5.21 x 10-3 m O 4.90 x 10 2M O 1.96 x 101 M O 3.92 x 103 M O None of the above

What is the sulfate ion concentration of the resulting solution when 75.0 mL of 1.50 M CuSO4 and 50.0 mL of 1.00 M Co2(SO4)3 are mixed together?

How many grams of magnesium phosphate, Mg3(PO4)2, would you need if you were required to make 270.0 mL of a magnesium phosphate solution with a concentration of 0.170 mol L-1? Molar masses:  Mg3(PO4)2 = 262.9 g mol-1    1 L = 1000 mL What is the concentration of PO43- ions in the 0.170 mol L-1 solution of magnesium phosphate?