Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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What transitional states are possible when a 4-bit asynchronous binary counter changes from
(a) count 2 to count 3 (b) count 3 to count 4
(c) count 1010 to count 1110 (d) count 15 to count 0
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- 2. Given the logic symbol for the 7485 IC (4-bit comparator). Use it to compare two binary numbers of 12 bit.arrow_forwardDesign a 3-bit counter which counts in the sequence: 001, 010, 110, 011, 111, 101, 100, (repeat) 001, ...arrow_forwardPlease answer the following question using only one 3-bit binary counter with clear input and the minimum number of components listed below, design a counter that generates the following sequence repeatedly: 0-> 3 -> 5 -> 7 -> 9 -> 11-> 13 -> 0 -> 3 -> 5 -> 7 …… Note: E is enable input. When E = 1, it counts at every clock cycle. When E = 0, it stops counting and output stays unchanged. clr is clear input. When clr = 1, it starts counting from 0 from the next clock cycle if E = 1. The allowed components are: a) 3-bit binary counter b) left and right shifter c) Logic Gates (And, Or, Not) (the number of input pins are not limited, which means that you can have more than 2 input pins)arrow_forward
- How many flip-flops will be complemented in a 10-bit binary ripple counter to reach the next count after the following counts?1. 10011001112. 11110001113. 0000001111arrow_forwardUsing a table similar to that shown in Figure 3.6, calculate the product of the octal unsigned 4-bit integers and 3 using the hardware described in Figure 3.3. You should show the contents of each register on each step. Iteration Step Multiplier Multiplicand Product 0011 Initial values 1a: 1= Prod = Prod + Mcand 0000 0010 0000 0000 1 0011 0000 0010 0000 0010 2: Shift left Multiplicand 3: Shift right Multiplier 1a: 1= Prod = Prod + Mcand 2: Shift left Multiplicand 3: Shift right Multiplier 1: 0> No operation 0011 0000 0100 0000 0010 0000 0100 0000 0010 0001 0000 0100 0000 0110 0000 1000 0000 1000 0001 0000 0110 0000 0000 0110 0000 0000 1000 0000 0110 2: Shift left Multiplicand 3: Shift right Multiplier 1: 0= No operation 0000 0001 0000 0000 0110 0000 0001 0000 0000 0110 4 0000 0001 0000 0000 0110 0010 0000 2: Shift left Multiplicand 3: Shift right Multiplier 0000 0000 0110 0000 0010 0000 0000 0110 FIGURE 3.6 Multiply example using algorithm in Figure 3.4. The bit examined to determine…arrow_forwardWrite in RTL Verilog. Use a 4-bit RCA, four 2-1 MUX, and four D-type flip-flops to implement a 4-bit counterarrow_forward
- Please send me answer of a,b and c in details and i will give you like sure sir please.arrow_forwardLike will be given if you do fastarrow_forward4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement numberINPUT B: 4 bit 2’s Complement numberOUTPUT: the product of A x B represented as a 8 bit 2’s Complement number Do this:Build a 4 Bit UNSIGNED Multiplier as a subcircuit named UnsignedMultiplier use AND gate ,full and half adders for the circuitarrow_forward
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