Chemistry
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ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![### Stoichiometry Problem: Determining Mass of KBr
**Problem Statement:**
What mass of KBr is produced when 18.5 moles of \( K_2SO_4 \) reacts?
**Chemical Equation:**
\[ \_\ AlBr_3 + \_\ K_2SO_4 \rightarrow \ KBr + \_\ Al_2(SO_4)_3 \]
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Balance the Chemical Equation:**
- Balance the reactants and products to ensure conservation of mass.
2. **Mole Ratio:**
- Determine the mole ratio between \( K_2SO_4 \) and KBr.
3. **Calculate Moles of KBr:**
- Use stoichiometry to convert moles of \( K_2SO_4 \) to moles of KBr.
4. **Find Mass of KBr:**
- Convert moles of KBr to mass using the molar mass of KBr.
Let's proceed through the solution step by step:
1. **Balancing the Equation:**
To balance the equation, we determine the coefficients:
\[ 2\ AlBr_3 + 3\ K_2SO_4 \rightarrow 6\ KBr + Al_2(SO_4)_3 \]
2. **Mole Ratio:**
From the balanced equation, the mole ratio of \( K_2SO_4 \) to KBr is 3:6, which simplifies to 1:2.
3. **Using the Mole Ratio:**
Given 18.5 moles of \( K_2SO_4 \):
\[
18.5\ moles\ K_2SO_4 \times \frac{6\ moles\ KBr}{3\ moles\ K_2SO_4} = 37\ moles\ KBr
\]
4. **Converting to Mass:**
The molar mass of KBr is approximately 119.0 g/mol. Therefore:
\[
Mass\ of\ KBr = 37\ moles \times 119.0\ g/mol = 4403\ g\ KBr
\]
Thus, when 18.5 moles of \( K_2SO_4 \) react, 440](https://content.bartleby.com/qna-images/question/a5817b45-79eb-4197-a96a-83d61446202e/602d85e1-fc6f-4c67-90c2-d415bb99a636/fxdv29f_processed.jpeg)
Transcribed Image Text:### Stoichiometry Problem: Determining Mass of KBr
**Problem Statement:**
What mass of KBr is produced when 18.5 moles of \( K_2SO_4 \) reacts?
**Chemical Equation:**
\[ \_\ AlBr_3 + \_\ K_2SO_4 \rightarrow \ KBr + \_\ Al_2(SO_4)_3 \]
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Balance the Chemical Equation:**
- Balance the reactants and products to ensure conservation of mass.
2. **Mole Ratio:**
- Determine the mole ratio between \( K_2SO_4 \) and KBr.
3. **Calculate Moles of KBr:**
- Use stoichiometry to convert moles of \( K_2SO_4 \) to moles of KBr.
4. **Find Mass of KBr:**
- Convert moles of KBr to mass using the molar mass of KBr.
Let's proceed through the solution step by step:
1. **Balancing the Equation:**
To balance the equation, we determine the coefficients:
\[ 2\ AlBr_3 + 3\ K_2SO_4 \rightarrow 6\ KBr + Al_2(SO_4)_3 \]
2. **Mole Ratio:**
From the balanced equation, the mole ratio of \( K_2SO_4 \) to KBr is 3:6, which simplifies to 1:2.
3. **Using the Mole Ratio:**
Given 18.5 moles of \( K_2SO_4 \):
\[
18.5\ moles\ K_2SO_4 \times \frac{6\ moles\ KBr}{3\ moles\ K_2SO_4} = 37\ moles\ KBr
\]
4. **Converting to Mass:**
The molar mass of KBr is approximately 119.0 g/mol. Therefore:
\[
Mass\ of\ KBr = 37\ moles \times 119.0\ g/mol = 4403\ g\ KBr
\]
Thus, when 18.5 moles of \( K_2SO_4 \) react, 440
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