Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![### Stoichiometry Problem: Determining Mass of KBr
**Problem Statement:**
What mass of KBr is produced when 18.5 moles of \( K_2SO_4 \) reacts?
**Chemical Equation:**
\[ \_\ AlBr_3 + \_\ K_2SO_4 \rightarrow \ KBr + \_\ Al_2(SO_4)_3 \]
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Balance the Chemical Equation:**
- Balance the reactants and products to ensure conservation of mass.
2. **Mole Ratio:**
- Determine the mole ratio between \( K_2SO_4 \) and KBr.
3. **Calculate Moles of KBr:**
- Use stoichiometry to convert moles of \( K_2SO_4 \) to moles of KBr.
4. **Find Mass of KBr:**
- Convert moles of KBr to mass using the molar mass of KBr.
Let's proceed through the solution step by step:
1. **Balancing the Equation:**
To balance the equation, we determine the coefficients:
\[ 2\ AlBr_3 + 3\ K_2SO_4 \rightarrow 6\ KBr + Al_2(SO_4)_3 \]
2. **Mole Ratio:**
From the balanced equation, the mole ratio of \( K_2SO_4 \) to KBr is 3:6, which simplifies to 1:2.
3. **Using the Mole Ratio:**
Given 18.5 moles of \( K_2SO_4 \):
\[
18.5\ moles\ K_2SO_4 \times \frac{6\ moles\ KBr}{3\ moles\ K_2SO_4} = 37\ moles\ KBr
\]
4. **Converting to Mass:**
The molar mass of KBr is approximately 119.0 g/mol. Therefore:
\[
Mass\ of\ KBr = 37\ moles \times 119.0\ g/mol = 4403\ g\ KBr
\]
Thus, when 18.5 moles of \( K_2SO_4 \) react, 440](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5817b45-79eb-4197-a96a-83d61446202e%2F602d85e1-fc6f-4c67-90c2-d415bb99a636%2Ffxdv29f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Stoichiometry Problem: Determining Mass of KBr
**Problem Statement:**
What mass of KBr is produced when 18.5 moles of \( K_2SO_4 \) reacts?
**Chemical Equation:**
\[ \_\ AlBr_3 + \_\ K_2SO_4 \rightarrow \ KBr + \_\ Al_2(SO_4)_3 \]
**Solution Explanation:**
To solve this problem, follow these steps:
1. **Balance the Chemical Equation:**
- Balance the reactants and products to ensure conservation of mass.
2. **Mole Ratio:**
- Determine the mole ratio between \( K_2SO_4 \) and KBr.
3. **Calculate Moles of KBr:**
- Use stoichiometry to convert moles of \( K_2SO_4 \) to moles of KBr.
4. **Find Mass of KBr:**
- Convert moles of KBr to mass using the molar mass of KBr.
Let's proceed through the solution step by step:
1. **Balancing the Equation:**
To balance the equation, we determine the coefficients:
\[ 2\ AlBr_3 + 3\ K_2SO_4 \rightarrow 6\ KBr + Al_2(SO_4)_3 \]
2. **Mole Ratio:**
From the balanced equation, the mole ratio of \( K_2SO_4 \) to KBr is 3:6, which simplifies to 1:2.
3. **Using the Mole Ratio:**
Given 18.5 moles of \( K_2SO_4 \):
\[
18.5\ moles\ K_2SO_4 \times \frac{6\ moles\ KBr}{3\ moles\ K_2SO_4} = 37\ moles\ KBr
\]
4. **Converting to Mass:**
The molar mass of KBr is approximately 119.0 g/mol. Therefore:
\[
Mass\ of\ KBr = 37\ moles \times 119.0\ g/mol = 4403\ g\ KBr
\]
Thus, when 18.5 moles of \( K_2SO_4 \) react, 440
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 8 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY