What is the value of Kp

Consider the following reaction:                                     CaF2 (s) + H2SO4 (l)  →   2 HF (g) +  CaSO4 (s)                ΔGfo = -8.48 kJ/mol at 450 K A mixture of calcium fluoride and sulfuric acid are allowed to react at 450 K. If ΔG is -5.6 kJ/mol, calculate the concentration of HF to two decimal places.

The difference in standard free energy between reactant R and product P is + 7.5 kJ/mol. What’s the ratio of P to R at equilibrium? P to R ratio =

Calculate the Kp.

The standard free energy change for the reaction CH4(g)+2O2(g) -> CO2(g) + 2H2O(l) is -194.8 kcal at 25ºC and -191.82 kcal at 75ºC. Calculate the heat of reaction at 25ºC.Ans: -212.6 kcal

Which of the following change will shift the equilibrium to the right for the following reaction?                 CaCO3(s) ------> CaO(s) + CO2(g) Group of answer choices Increasing CaCO3(s) Decreasing the pressure Decrease CaO(s) Increasing CO2 (g)

Calculate the AH°, AS°, and AG° at 298 K for the following reaction: (Use the values found in Thermodynamic Properties to calculate your answers for questions a and b.) Al2O3(s) + 3 C(graphite) + 3 Cl₂(g) → 2 AICI3(s) + 3 CO(g) a) ΔΗο 400-64 kJ/mol b) AS° J/K.mol c) AGO 4.0 ✔ kJ/mol (Determine from the temperature, AH and AS) (d) Is the reaction extensive at standard conditions and 298 K? O Yes O NO 4.0 76.9 -89 (e) Write the expression for K. (Format example: Kp = pHC1² / pH₂. pCl2 would be entered as K_{p} = pHCI^{2}/pH_{2} . pCl_{2}.) Help chemPad X₁X (PCO)³ (pCl₂)3 Greek (PCO)^3/(pCl_2)^3 Your answer provides a different type of equation than was expected. (f) Calculate the value of K at 298 K 2.51e-16 X (Please answer to 3 significant figures.) (g) Estimate the value of K at 600 K. 1 79e-8 Ty (Please answer to 3 significant figures)

Using the information from appendix G, calculate the value of K for the following equilibrium at 25oC.  O2(g)  +  O(g) ⇆  O3(g)

An empty steel container is filled with 5.30 atm of H2 and 5.30 atm of F2. The system is allowed to reach equilibrium. If Kp = 0.450 for the reaction below, what is the equilibrium partial pressure of HF? %3D H2 (g) + F2 (g) =2 HF (g)

The standard free energy of formation of ammonia at 298 K is -16.5 kJ/mol. What is the value of Kp for the reaction at 298 K? (R = 8.314 J/mol. K) N2 (g) + 3H2 (g) ⇌ 2NH3 (g)