What is the value of k so that the differential equation (y³ + kxy4 − 2x)dx + (3xy² + 20x²y³)dy = 0 becomes exact? OA. 5 OB.-5 O C. 10 O D.-10 O E. None of the Choices

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A: Given Equation: 3(3x2+y2)dx-2xydy=0 ⇒3(3x2+y2)dx=2xydy ⇒dydx=3(3x2+y2)2xy------(i)

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