What is the time complexity of the following code?for(int i=1;i<=N; i++)for(int j=1; j<= N*N; j++)print(i*j):a. O( N?)O b. O( N? log N)O. O(N³ )O d. None of them

Answered: What is the time complexity of the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Find the space complexity of the following code fib(int n) { if (n <= 1) return n; return fib(n-1) + fib(n-2); }
a) You are given two different codes for finding the n-th Fibonacci number. Find the time complexity of both implementations and compare the two. Implementation 1 def fibonacci_1 (n) : if n < 0: print ("Invalid input!") elif n <= 1: return n else: return fibonacci_1 (n-1) +fibonacci_1 (n-2) n = int (input ("Enter a number: ")) nth_fib= fibonacci_1 (n) print("The {}th fibonacci number is {}.". format (n, nth_fib)) Implementation 2 def fibonacci_2 (n) : if n<0: return "Invalid Input" if n<=1: return n fib [0] (n+1) fib[0] = 0 fib[1] = 1 for i in range (2, n+1): fib[i] = fib[i-1]+ fib[i-2] return fib[n] n = int(input ("Enter a number: ")) nth_fib = fibonacci_2 (n) print("The {} th fibonacci number is {}.". format (n, nth_fib))
Trace the following code and write what it does. void Finals(X, Y, m, n) { int i=1, j-1, k=13; while (i <=m && j<=n) { if (X[i]
Find the values of n and m to solve this puzzle int n = ? int m = ? int t = 76; int s = 0; char *msg = "Do you like spaghetti? Try some spaghetti! It's good, right?\n" "What, you prefer structured loops? How mundane.\n"; goto LTOP; LEND: failure(msg); LOM1: n = (n<<2) - n + 1; LCHK: if(s == t && m == t){ goto LAFT; } s++; goto LTOP; LOC1: if(n & 1){ goto LOM1; } goto LEM1; LTOP: if(!(n>1)){ goto LEND; } goto LOC1; LEM1: n = n >> 1; goto LCHK; LAFT: return;
def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ":") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(h) s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) If i don't one the output have the square braket? How can I fix this code? Can you pleasw help me?
Write a program to display find and display the duplicate numbers in the given array of elements.Input:Enter array of elements: 10 20 1 3 4 1 2 10 1 8Output:Duplicate elements in the given array of elements are10 (2 times)1 (3 times)
List two ways to rewrite the following code with code optimization methods for(i=0;i
def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ": ") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(*h) print(",") s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) How can I fix this code if I want a comma between each number, not each line?
JAVA Make a function that will get the value of ln(n!). use Math.log() function in replace to ln()
No plagarism please! Correct and detailed answer will be Upvoted else downvoted. Thank you!
1. Analyze the time complexity of the code segment and find their Big-O.void myfunction1(int n){for(int i=0; i < n; i++) {for(int j=0; j < n; j++) {for(int k=0; k < n; k++) {for(int m=0; m < n; m++) {printf("Hello!");} } } }}

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What is the time complexity of the following code? for(int i=1;i<=N; i+ +) for(int j=1; j<= N*N; j++) print(i"j): a. O(N?) O b. O(N2 log N) O. O(N³) O d. None of them