What is the stereochemical configuration of this compound? Numbering starts at the aldehydic carbon. 1 ОНС ОН H Б 2R, 3R • 2S, 3R • 2R, 3S ° 2S, 3S НО 3 CH OH 4
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- Under certain reaction conditions, 2,3-dibromobutane reacts with two equivalents of base to give three products, each of which contains two new p bonds. Product A has two sp hybridized carbon atoms, product B has one sp hybridized carbon atom, and product C has none. What are the structures of A, B, and C?1. Name compounds by IUPAC nomenclature CH₂CH-COOH a ОН 2) Find all of the heterofunctional compounds among following: ОН 2 сн, -ен, -с NH, OH COOH CH-OH CH,COOH e b COOH H-C-OH н-с- -ОН COOH -СООН f с H₂C-C-CH₂ 0 COOH HO-C-CH,COOH CH,COOH CH2-CH-CH2; OH ОН ОН g d ОН HOOC–C–CH,COOH ОН HOỌC –COOH б ONaClassify the carbocations as 1º, 2º, or 3º, and rank the carbocations in each group in order of increasing stability.
- 4. Ring Inversion of Substituted Cyclohexane 4.1 Two Chair Conformations of Substituted Cyclohexane Rings boat conformation is 30 hair conformation. Thus, the equilibrium favors the chair conformations. _kJ/mol higher ● ● When Ring Flipping Occurs If a substituent is initially in the axial position, after ring flipping it will be in the position (and vice-versa). equatorial 4 5 5 Connectivity does NOT change. Substituents stay on the same side of the ring that they started on! The cis-trans relationships do NOT change (cis groups stay cis and trans groups stay trans.) H3C Pown 6 3 3 6 CH3 1 CH3 2 1 2 eq I I CH3 H 180N -I 6 in energy than the down ax CH₂ On up on C 1Name the following compound: Br O (1S, 3S,4R)-1-chloro-3-bromo-4-isopropylcyclohexane O (1R, 2R, 5R)-1-bromo-2-isopropyl-5-chlorocyclohexane O (1R, 2S, 4R)-2-bromo-4-chloro-1-isopropylcyclohexane O (1S, 25, 4R)-2-bromo-4-chloro-1-isopropylcyclohexane O (15, 25, 5R)-1-bromo-2-isopropyl-5-chlorocyclohexane2. The following molecule is one enantiomer of methylenedioxymethamphetamine (MDMA). 2a. Circle all of the stereocenters in MDMA 2b. Assign the absolute stereochemistry (R or S) for each stereocenter .CH3 HN H H *CH3
- Compounds 1 and 2 were prepared, and the difference in their heats of combustion was found to be 17.2 kJ/mol (J. Am. Chem. Soc. 1961, 83, 606-614): H H 1 Shown below are the lowest-energy conformations of compounds 1 and 2. Identify which drawing matches which compound, and identify which compound has the larger heat of combustion. H H H H |||I 2 H 4 H H The first drawing is compound 1, and compound 1 has a larger heat of combustion because it is the less stable compound. O The first drawing is compound 2, and compound 2 has a larger heat of combustion because it is the less stable compound. The first drawing is compound 2, and compound 2 has a larger heat of combustion because it is the more stable compound. The first drawing is compound 1, and compound 1 has a larger heat of combustion because it is the more stable compound.Identify the stereochemical configuration of this compound. SH CH3 O R SStereochemistry of hydroboration. There are two products that result from this reaction. Products 1 and 2 are stereoisomers of each other. The first product is thermodynamically more stable than the second product. Draw how the two products will look like. Also draw the most stable conformation of the first product. OH J 1. 9-BBN, THF 2. H₂0₂, H₂O, NaOH
- Following is a staggered conformation for one of the enantiomers of 2-bromobutane, and several purported Newman projections for this conformation. H H H3C Br H CH3 2-bromobutane H H (a) Is this (R)-2-bromobutane or (S)-2-bromobutane? CH3 CH3 Br H H H CH3 Br b CH3 H Br H CH3 CH3 H (b) Which of the following Newman projections is equivalent to the wedge-dash structure when viewed along the horizontal axis?Hil H H C6H5-C-C-C6H5 C6H5 + HCI C6H5 H. ÓH ČI This equation shows the reaction of trans-2,3-diphenyloxirane with hydrogen chloride to form 2-chloro-1,2-diphenylethanol. How many total stereoisomers are possible for 2-chloro-1,2-diphenylethanol? 4 Given that opening of the epoxide ring in this reaction is stereoselective, provide the names of the only two isomeric products formed using IUPAC guidelines. product 1: (1R 2R) product 2: ((1S 2S) v 2-chloro-1,2-diphenylethanol 2-chloro-1,2-diphenylethanol Try Another Version 1 item attempt remaining Submit Answer4. A double bond in a six-membered ring is usually more stable in an endocyclic position than in an exocyclic position. Hydrogenation data on two pairs of compounds follow. One pair suggests that the energy difference between endocyclic and exocyclic double bonds is about 9 kJ/mol. The other pair suggests an energy difference of about 5 kJ/mol. Which number do you trust as being more representative of the actual energy difference? Explain your answer. endocyclic exоcyclic 107 116 105 110 heats of hydrogenation (kJ/mol)