MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Question
What is the smallest value of k in Chebyshev’s theo-
rem for which the probability that a random variable will
rem for which the probability that a random variable will
take on a value between μ − kσ and μ + kσ is
(a) at least 0.95;
(b) at least 0.99?
(a) at least 0.95;
(b) at least 0.99?
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- The annual rainfall (in inches) in a certain region is normally distributed with µ = 40 and σ = 4. What is the probability that starting with this year, it will take more than 10 years before a year occurs having a rainfall of more than 50 inches? Suppose the rainfall in each year is independent of the rainfall in other years and the distribution of rainfall in each year is the same as in the present year.arrow_forwardThe time that it takes to service a car is an exponential random variable with rate 1.1. If A brings his car in at time 0 and B brings his car in at time t, what is the probability thatB’s car is ready before A’s? Assume that the service times are independent, and the servicebegins upon arrival.2. If both cars are brought in at time 0, with work starting on B’s car only when A’s car has beencompletely serviced, what is the probability that B’s car is ready before 2? Detailed explanation and calculation would be much appreciated.arrow_forwardSuppose we wish to estimate the expectation of a random variable X with a large popula- tion. We observe n members of the population, i.e. {x;}1. Individual i is included in the sample with a probability proportional to p;. Please demonstrate that the usual sample E; ®i/Pi i=1• mean ī = n-1E, xi is no longer a consistent estimator for E[X], but ã is. E; 1/Pj vi=1arrow_forward
- 8. The time (in minutes) that it takes a car mechanic to replace a car battery is a random variable X that follows an exponential distribution with mean 15 minutes. a) Find P(14 < X < 22). Round off your answer to two decimal places. x 22 1 P(14 < X <22) = √₂/1² 15 e 15dx = P(x < 22) — P(x < 14) x 15 122 = e 15 22 1 - e 14 or 0.8 = = 22 14 = −e 15 + e15 = 0.16254≈ 0.16 - (1 – b) Find the 80th percentile. Round off to the nearest whole number. 1 X S 15 14 e 15 t e 15 dt X 0.8 = 1 e 15 X e 15 = = 0.2 14 22 = e 15 e 15 = 0.16 x — = ln (0.2). This gives x = 24.14156 15arrow_forwardIf x is a binomial random variable, compute p(x) for each of the following cases: (a) n = 6, x = 2, p = 0.9 p(x) = (b) n = 6, x = 1, p = 0.3arrow_forward
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