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- Question 1 I= Part (a) I measure the resistance of this wire and find it to be R = 156 Q2. What is the resistivity of the material the wire is made out of? p=5.182 *10-4 p=5.182 x 10-4 ✓ Correct! Part (b) What is the conductivity of this wire, in inverse Ohms per meter? 1930. ✓ Correct! o=1929.8 Part (c) Part (c) Give an expression for the current density in the wire if an electric field E is passing through it. Write this in terms of the resistivity and the other variables in the problem. A particular wire has a length of L = 2.7 m and a circular cross-sectional area of radius r = 1.69 mm. X J= EL/Rar² x J= E/p Question 2 Correct Answer E-Pat sin()) cotan() atan() cosh() E-4.752x10 ✓ Correct! B 8 L P Student Final Submission E-Pat Part (b) How much energy has been used in joules? Y d h m 7 Part (d) Calculate the current in the wire, in milliamperes, if the field strength is 5.28 V/m. r cos() asin() acotan() sinh() tanh() cotanh() Degrees O Radians You leave a 110 W light bulb on for…51&page=1 What is the resistance (in units of Q) of a wire made of a material with a resistivity of 3.2 x 10-8 Q. m, if its length is 10.7 m and its diameter is 0.50 mm? Select one: O A. 6.02 OR. 0.67 OC.0.44 OD. 3.88 OE. 1.74 Next page 601 AM A O G d ENG 4/15/2021Resistance in metals increases with increasing temperature according to the equation, ρ(T) = ρo(1 + α(T - To)) where α is the temperature coefficient of resistivity and ρo is the resistivity at temperature To. For a particular wire α = 9.5 × 10-3 1/°C and the resistivity is ρo = 4.5 × 10-7 Ω⋅m at To = 154 °C. a). Input an expression for the temperature T2 at which the resistance of a wire will be twice as high as at T0. b). If the wire is L = 1 m long with a radius of r = 1 cm, what is its resistance R, in Ω, at 2To?
- a. What diameter of copper wire [p = 2.65 x 10^-8 ohm.m) should be used so that a 22.0 m length will have a resistance of 0.39 ohm? b. Find the temperature coefficient of resistivity for this wire if an increase in temperance of 120 degree C changes the resistance from 0.39 ohm to 0.62 ohm.25.69 A 1.50-m cylinder of radius 1.10 cm is made of a complicated mixture of materials. Its resistivity depends on the distance x from the left end and obeys the formula rho(x) = a + bx2, where a and b are constants. At the left end, the resistivity is 2.25 X 10-8 Ohm-meters, while at the right end it is 8.50 X 10-8 Ohm-meters. (a) What is the resistance of this rod? (b) What is the electric field at its midpoint if it carries a 1.75-A current?that pass per second through a section of wire carrying a A. E. Solve for the resistance of a conductor given a resistivity of 15.3 £-m, length of 6m, and cross sectional area of 2.85 x 10² m². F. A copper rod is 3 m long and 4 mm in diameter. Compute its resistance if the resistivity of the material is 1.76 x 108 -m. G. A piece of number 10 aluminum wire has a diameter of 2.59 mm. How many meters of number 10 aluminum wire is needed to give a resistance of 1 ? Aluminum has p of 2.8 x 10³ Q-m. H. Compute the Resistance of a 190 m wire made of silver having a cross-sectional area of 0.55 mm². Silver has a resistivity of 1.6 x 10³ N-m.
- What is the resistance (in units of Q) of a wire made of a material with a resistivity of 3.2 × 10-8 Q . m , if its length is 39.3 m and its diameter is 0.50 mm? Select one: A. 2.47 B. 22.12 OC. 6.40 D. 14.26 O E. 1.60A cylindrical conductor has resistance of R0 = 120 Ω. It has length L, radius of the cross section r, and resistivity ρ. Part (a) Express the resistance in terms of L, r, ρ. R0 = P L/π r2 This equation is incorrect Part (b) If the resistivity increases by a factor of 5, what would the value of the new resistance be, in ohms? Rρ =600 Part (c) If the resistivity was restored to its original value and instead the length of the conductor decreased by a factor of 5, what would the value of the new resistance be, in ohms? Rl = Part (d) If the resistivity and length of the conductor were at their original values and the radius of the conductor increased by a factor of 4, what would be the value of the new resistance, in ohms? Rr =What is the resistance (in units of Q) of a wire made of a material with a resistivity of 3.2 × 10-8 Q . m , if its length is 22.2 m and its diameter is 0.50 mm? Select one: A. 8.06 B. 3.62 C. 12.50 D. 1.40 E. 0.90
- A wire of length L and cross-sectional area A has a resistivity p. Which of the following formulas can be used to calculate the resistance of the wire? L A Select one: A a. R = pL b. R = PL A С. d. R =L A e. R = - PA е.A wire is made of a material with a resis- tivity of 2.97138 x 10-8 2 · m. It has length 2.16443 m and diameter 0.20515 mm. What is the resistance of the wire? Answer in units of N.3:08 l LTE Youngstown State University Edit Friday 9:58 AM 1. A conductor of radius r, length l and resistivity p has resistance R. It is melted down and formed into a new conductor, also cylindrical, with one fourth the length of the original conductor. What is the resistance of the new conductor? (Hint: the volume stays the same) 16R a. b. 4R c. 1. d. 4 iR 16R e.