
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Transcribed Image Text:What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value?
Express your answer with the appropriate units.
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![The integrated rate law allows chemists to predict the reactant concentration after a certain amount of
time, or the time it would take for a certain concentration to be reached.
The integrated rate law for a first-order reaction is:
Half-life equation for first-order reactions:
0.693
t1/2 =
[A] = [A]oe-kt
where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s).
Now say we are particularly interested in the time it would take for the concentration to become one-
[A],
half of its initial value. Then we could substitute " for [A] and rearrange the equation to:
0.693
t1/2
This equation calculates the time required for the reactant concentration to drop to half its initial value.
In other words, it calculates the half-life.](https://content.bartleby.com/qna-images/question/65639ce4-957e-4e3f-ad7d-82256b02ea7d/6a3901bd-0afc-4d57-b7bd-7f2d431fb8f8/bk35yto_thumbnail.png)
Transcribed Image Text:The integrated rate law allows chemists to predict the reactant concentration after a certain amount of
time, or the time it would take for a certain concentration to be reached.
The integrated rate law for a first-order reaction is:
Half-life equation for first-order reactions:
0.693
t1/2 =
[A] = [A]oe-kt
where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s).
Now say we are particularly interested in the time it would take for the concentration to become one-
[A],
half of its initial value. Then we could substitute " for [A] and rearrange the equation to:
0.693
t1/2
This equation calculates the time required for the reactant concentration to drop to half its initial value.
In other words, it calculates the half-life.
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