What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. • View Available Hint(s) Templates Symbols undo redo Peset keyboard shortcuts help Value Units

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value?
Express your answer with the appropriate units.
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Transcribed Image Text:What is the rate constant of a first-order reaction that takes 490 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. • View Available Hint(s) Zeset Templates Symbols undo redlo keyboard shortcuts help Value Units
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of
time, or the time it would take for a certain concentration to be reached.
The integrated rate law for a first-order reaction is:
Half-life equation for first-order reactions:
0.693
t1/2 =
[A] = [A]oe-kt
where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s).
Now say we are particularly interested in the time it would take for the concentration to become one-
[A],
half of its initial value. Then we could substitute " for [A] and rearrange the equation to:
0.693
t1/2
This equation calculates the time required for the reactant concentration to drop to half its initial value.
In other words, it calculates the half-life.
Transcribed Image Text:The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: Half-life equation for first-order reactions: 0.693 t1/2 = [A] = [A]oe-kt where t/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s). Now say we are particularly interested in the time it would take for the concentration to become one- [A], half of its initial value. Then we could substitute " for [A] and rearrange the equation to: 0.693 t1/2 This equation calculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life.
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