What is the product of this reaction? O 1. LDA, -78, °C O 2. 3. H3O+ H

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Add curved arrows to each step in the attached reaction sequence.

Show the mechanism for this reaction of alkynes

29 minutes, 42 seconds. Question Completion Status: A Moving to another question will save this response. Question 15 What is not an expected product of the following allylic substitution reaction? NBS, hv Br Br Compounds II and II Compound II only O Compound I only O Compound II only A Moving to another question will save this response O O C

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What is the complete mechanism for this F!she rxn?

Select the TWO most nucleophilic atoms in this molecule. HS

Complete the mechanism for the keto-enol tautomerization shown using bonds, charges, nonbonding electron pairs, and curved arrows (forward reaction only). Do not delete any pre-drawn bonds, charges, or lone pairs. If you accidentally delete a vital part of the structure, click the undo button in the lower left. Step 1: keto form. Draw curved arrows. Step 2: complete the structure, then add curved arrows. Select Draw Rings More Erase Select Draw Rings More Erase H H - H :0: :0: :o: 1L :o:

Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…