What is the predicted response value? (Report answer accurate to one decimal place.) y = ___________
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Ch. 21 part 2
Run a
| x | y |
|---|---|
| 43.8 | 54.1 |
| 41.3 | 51.2 |
| 35.3 | 60.1 |
| 48.1 | 44.9 |
| 42.8 | 51.8 |
| 44.7 | 50.8 |
| 39.4 | 56.6 |
| 38.2 | 56.6 |
| 40.7 | 53.5 |
| 45.3 | 51.1 |
| 45 | 46.7 |
| 41.1 |
52.2 |
Predict what value (on average) for the response variable will be obtained from a value of 40.1 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.
What is the predicted response value? (Report answer accurate to one decimal place.)
y = ________________
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- A customer service department asks its customers to rate their over-the-phone service on a scale of 1-20 immediately after their service has been completed. The department then matches each customer's rating with the number of minutes the person waited on hold. The accompanying table shows the ratings and number of minutes on hold for 10 randomly selected customers. The regression line for the data is y=17.02−0.464x. Minutes Rating 4 16 8 12 1 17 6 10 7 13 1 17 10 15 3 19 7 15 3 13 R2= 0.274 α=0.05 F-test statistic is 3.02 The p-value is 0.121 Construct a 95% confidence interval for the average rating given by a customer who waits 8 minutes. UCL = (Round to two decimal places as needed.) LCL = (Round to two decimal places as needed.)Run a regression analysis on the following bivariate set of data with y as the response variable. x y 72.7 1.8 42.1 83.2 60.4 73.6 41.9 87.1 60.3 70.3 48.6 54.7 42.1 57.3 32.8 96.6 44.6 88.7 71.5 65.7 39.5 98.4 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 12.4 on the response variable.What is the predicted explanatory value?x =Here is a bivariate data set. Find the regression equation for the response variable y. x y 53.1 67.6 50.1 60.1 44.8 57.9 42.6 48.7 44.3 57 35.7 50.4 44.5 56.5 45.7 54.4 45 51.6 48 55.9 47.2 60.5 50.3 62.5 48.6 60.9 regression equation: Enter the equation in slope-intercept form with parameters accurate to three decimal places.
- Run a regression analysis on the following bivariate set of data with y as the response variable. x y 58.3 81.3 77.7 48.5 49.3 67.2 68.5 58.9 46.4 93.1 65.5 75.8 48.9 90.5 65.2 66.9 63.2 79.4 56.5 89.3 65.6 75.5 40.4 96.2 Find the correlation coefficient and report it accurate to three decimal places. r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %Based on the data, calculate the regression line (each value to three decimal places)y = x + Predict what value (on average) for the response variable will be obtained from a value of 77.8 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.What is the predicted response value? (Report answer accurate to one decimal place.)y =Run a regression analysis on the following bivariate set of data with y as the response variable. X y 9.4 24.2 36.9 66.5 42.6 140.4 -16 -26.1 27.4 52 27.5 71.9 24.8 66.8 21 41.2 33.1 2.4 23.9 34.4 69.2 34.3 71.9 66 Find the correlation coefficient and report it accurate to three decimal places. r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) r² = % Based on the data, calculate the regression line (each value to three decimal places) y = X + Predict what value (on average) for the response variable will be obtained from a value of -13.4 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y =Run a regression analysis on the following bivariate set of data with y as the response variable. x y 43.2 -8.5 114.8 171 73.3 87.5 58.4 57.9 68.2 37.2 70.6 90.4 61.4 82.1 87.1 79.6 58 -9.2 78.4 77.2 80.5 87.3 64.1 22.9 54.3 32 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 20.7 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
- Run a regression analysis on the following bivariate set of data with y as the response variable. x y 68.5 65.9 88.3 71.6 66.1 61.2 63.6 59.1 67.6 56.7 34.3 47.4 65.4 58.4 59.6 61.1 60.6 54.6 55.2 59.5 67.1 60.7 60.6 57.5 Find the correlation coefficient and report it accurate to three decimal places.r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %Based on the data, calculate the regression line (each value to three decimal places)y = x + Predict what value (on average) for the response variable will be obtained from a value of 81.6 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value? (Report answer accurate to one decimal place.)y =…Here is a bivariate data set. Find the regression equation for the response variable y. x y 60.9 36.2 55.8 44.3 27.8 61.7 36.1 56.3 56 53.7 49.8 55.2 45.7 51.5 60.1 46.6 63.1 50 63.9 40.2 68.8 45.4 32.3 60.4 76.6 40.6 65.4 46 65.6 42.7 regression equation: Enter the equation in slope-intercept form with parameters accurate to three decimal places.Run a regression analysis on the following bivariate set of data with y as the response variable. X y 9.8 75.6 17.1 50.7 62 71.6 41.4 60.4 44.8 37.7 52.6 40.6 60.1 10.4 55.6 38.9 74.2 -6.6 49.7 33.6 43.9 54.8 Verify that the correlation is significant at an a = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 45.9 on the response variable. What is the predicted explanatory value? X =
- Run a regression analysis on the following bivariate set of data with y as the response variable. x y 34.4 51.4 21.3 55.8 42.1 45.1 46 44.3 16.6 64 45.5 45.9 41.8 38.8 20.8 56.6 27.6 52.9 12 66.2 35.6 52.4 21.6 57.4 Predict what value (on average) for the response variable will be obtained from a value of 36.9 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?y = (Report answer accurate to one decimal place.)Run a regression analysis on the following bivariate set of data with y as the response variable. 58.6 53.6 20 43 24.6 44.1 9.7 40.8 55.1 57.4 -10.3 33.1 39.1 44.9 27.8 48.4 2 33.8 37.6 51.2 52.5 54.3 -12.6 35 Find the correlation coefficient and report it accurate to three decimal places. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%.you would enter 84.5 without the percent symbol.) 9% Based on the data, calculate the regression line (each value to three decimal places) y = x+ Predict what value (on average) for the response variable will be obtained from a value of 53 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y =Here is a bivariate data set. Find the regression equation for the response variable y. X y 32.6 50.4 56.5 9.4 74.6 8.8 42.6 86.6 73.8 -16.6 66.4 29.6 53.9 28.5 40.7 93.7 33.2 88.1 65.9 5.2 52.9 46.9 regression equation: Enter the equation in slope-intercept form with parameters accurate to three decimal places.
