What is the predicted response value? (Report answer accurate to one decimal place.) y = ___________

Run a regression analysis on the following bivariate set of data with y as the response variable. x y 58.3 81.3 77.7 48.5 49.3 67.2 68.5 58.9 46.4 93.1 65.5 75.8 48.9 90.5 65.2 66.9 63.2 79.4 56.5 89.3 65.6 75.5 40.4 96.2 Find the correlation coefficient and report it accurate to three decimal places. r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place.  (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %Based on the data, calculate the regression line (each value to three decimal places)y = x + Predict what value (on average) for the response variable will be obtained from a value of 77.8 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.What is the predicted response value?  (Report answer accurate to one decimal place.)y =

Run a regression analysis on the following bivariate set of data with y as the response variable. X y 9.4 24.2 36.9 66.5 42.6 140.4 -16 -26.1 27.4 52 27.5 71.9 24.8 66.8 21 41.2 33.1 2.4 23.9 34.4 69.2 34.3 71.9 66 Find the correlation coefficient and report it accurate to three decimal places. r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) r² = % Based on the data, calculate the regression line (each value to three decimal places) y = X + Predict what value (on average) for the response variable will be obtained from a value of -13.4 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y =

Run a regression analysis on the following bivariate set of data with y as the response variable. x y 43.2 -8.5 114.8 171 73.3 87.5 58.4 57.9 68.2 37.2 70.6 90.4 61.4 82.1 87.1 79.6 58 -9.2 78.4 77.2 80.5 87.3 64.1 22.9 54.3 32 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 20.7 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)

Run a regression analysis on the following bivariate set of data with y as the response variable. x y 68.5 65.9 88.3 71.6 66.1 61.2 63.6 59.1 67.6 56.7 34.3 47.4 65.4 58.4 59.6 61.1 60.6 54.6 55.2 59.5 67.1 60.7 60.6 57.5 Find the correlation coefficient and report it accurate to three decimal places.r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place.  (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %Based on the data, calculate the regression line (each value to three decimal places)y =  x + Predict what value (on average) for the response variable will be obtained from a value of 81.6 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?  (Report answer accurate to one decimal place.)y =…

Here is a bivariate data set. Find the regression equation for the response variable y. x y 60.9 36.2 55.8 44.3 27.8 61.7 36.1 56.3 56 53.7 49.8 55.2 45.7 51.5 60.1 46.6 63.1 50 63.9 40.2 68.8 45.4 32.3 60.4 76.6 40.6 65.4 46 65.6 42.7 regression equation:     Enter the equation in slope-intercept form with parameters accurate to three decimal places.

Run a regression analysis on the following bivariate set of data with y as the response variable. X y 9.8 75.6 17.1 50.7 62 71.6 41.4 60.4 44.8 37.7 52.6 40.6 60.1 10.4 55.6 38.9 74.2 -6.6 49.7 33.6 43.9 54.8 Verify that the correlation is significant at an a = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 45.9 on the response variable. What is the predicted explanatory value? X =

Run a regression analysis on the following bivariate set of data with y as the response variable. x y 34.4 51.4 21.3 55.8 42.1 45.1 46 44.3 16.6 64 45.5 45.9 41.8 38.8 20.8 56.6 27.6 52.9 12 66.2 35.6 52.4 21.6 57.4 Predict what value (on average) for the response variable will be obtained from a value of 36.9 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?y = (Report answer accurate to one decimal place.)

Run a regression analysis on the following bivariate set of data with y as the response variable. 58.6 53.6 20 43 24.6 44.1 9.7 40.8 55.1 57.4 -10.3 33.1 39.1 44.9 27.8 48.4 2 33.8 37.6 51.2 52.5 54.3 -12.6 35 Find the correlation coefficient and report it accurate to three decimal places. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%.you would enter 84.5 without the percent symbol.) 9% Based on the data, calculate the regression line (each value to three decimal places) y = x+ Predict what value (on average) for the response variable will be obtained from a value of 53 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y =

Here is a bivariate data set. Find the regression equation for the response variable y. X y 32.6 50.4 56.5 9.4 74.6 8.8 42.6 86.6 73.8 -16.6 66.4 29.6 53.9 28.5 40.7 93.7 33.2 88.1 65.9 5.2 52.9 46.9 regression equation: Enter the equation in slope-intercept form with parameters accurate to three decimal places.