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What is the pH of 0.45 mol/L solution of hypochlorous acid? (K = 3.0 x 10")

What is the pH of 0.45 mol/L solution of hypochlorous acid? (K = 3.0 x 10")

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the pH of 0.45 mol/L solution of hypochlorous acid?

(K = 3.0 x 10")

 

ng activity 3.7: Resisting change buffers 27 MINDS ON ACTION Try to answer the following questions on buffer calculations and also on weak acid/base calculations. When you have completed your answers to these questions, you can submit using the portfolio tool to your teacher for feedback. In addition, if you need assistance you may use the following discussion forum to ask questions to your teacher or the class. Buffer Question 1: How do intermolecular forces contribute to the solubility of organic compounds? A 1.00L solution is made of 0.40mol/L NaNO2 and 0.25mol/L HNO2 (K₂ = 4.5 × 10−4) What is the pH of this solution? www. Sal Buffer Question 2: To this solution, 20.0mL of 0.15 mol/L HNO3 is added. What is the resulting pH?
Transcribed Image Text:ng activity 3.7: Resisting change buffers 27 MINDS ON ACTION Try to answer the following questions on buffer calculations and also on weak acid/base calculations. When you have completed your answers to these questions, you can submit using the portfolio tool to your teacher for feedback. In addition, if you need assistance you may use the following discussion forum to ask questions to your teacher or the class. Buffer Question 1: How do intermolecular forces contribute to the solubility of organic compounds? A 1.00L solution is made of 0.40mol/L NaNO2 and 0.25mol/L HNO2 (K₂ = 4.5 × 10−4) What is the pH of this solution? www. Sal Buffer Question 2: To this solution, 20.0mL of 0.15 mol/L HNO3 is added. What is the resulting pH?
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