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What is the output of the following pseudocode? count: 0 For i = 1 to 4 For ji+ 1 to 5 End-for End-for Return(count) count: count + i*j

What is the output of the following pseudocode? count: 0 For i = 1 to 4 For ji+ 1 to 5 End-for End-for Return(count) count: count + i*j

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question 2 What is the output of the following pseudocode? count := 0 For i = 1 to 4 For j = i + 1 to 5 count End-for End-for Return(count) count+i*j
Transcribed Image Text:Question 2 What is the output of the following pseudocode? count := 0 For i = 1 to 4 For j = i + 1 to 5 count End-for End-for Return(count) count+i*j
Expert Solution
Explanation

We have a pseudocode in question which uses a nested for loop. Below are details 

  • It initialize count variable as 0
  • It runs an outer for loop from i = 1 to 4. This will run for loop for value of i = 1, 2, 3.
    • It runs inner for loop from j = i to 5.
      • This will run for loop for value of j = 2, 3, 4 when i = 1
        • it accumulate sum of product of i and j in count variable
        • count = count + i*j
        • 2   = 0   + 1*2
        • 5   = 2   + 1*3
        • 9   = 5   + 1* 4
      • This will run for loop for value of j = 3, 4 when i = 2
        • it accumulate sum of product of i and j in count variable
        • count = count + i*j
        • 15 = 9   + 2*3
        • 23 = 15 + 2*4
      • This will run for loop for value of j = 4 when i = 3
        • it accumulate sum of product of i and j in count variable
        • count = count + i*j
        • 35  = 23+ 3*4
  • return value of count(35)
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