What is the maximum mass of S8 that can be produced by combining 82.0 g of each reactant? 8CO2 + 16H2S —-> 3S8 + 16H2O

For the experiment " limiting reactant " and after filtering the precipitate, you checked the filtrate (supernatant) to identify the limiting reactant. 2Na3PO4 + 3BaCl2 → Ba3(PO4)2 (s) + 6NACI If you added BaCl2 to the filtrate (supernatant) and a white precipitate was formed, this means that: O a. None of the mentioned O b. BaCl2 is an excess Oc. Both BaC2 and Na3PO4 are limiting reactants O d. BaCl2 is the limiting reactant O e. NagPO4 is the limiting reactant

6.) What is the maximum mass of H20 that Can be produced by Combining 66.4g of each reactant. 4NH3 (g) + 5O₂ (g) → 4NO(g) + 6 H ₂ O (g)

Consider the reaction between ammonium and oxygen: 4 NH3 ) + 5 02 () --> 4 NO ) + 6 H20() A chemist allows 10.8 g of NH3 and 5.30 g of O2 to react. When the reaction is finished, the chemist collects 3.00 g NO. Determine the percent yield for the reaction.

Consider the following reaction. Na2CO3 + Mg(NO3)2 --> MgCO3 + 2NaNO3 Assuming the reaction goes to completion, when 25 mL of a 0.1 M Na2CO3 solution reacts with 22 mL of a 0.3 M Mg(NO3)2 solution, what is the maximum nuber of grams of MgCO3 that can produce? Which is the limiting reactant in the chemical reaction?

Balance the chemical equation. What is the coefficient in front of O₂? C3H8(1) + ? O2(g) →→→ CO2(g) + H₂O(g) 02 3 O4 05 none of these

according to the equationP4(s)+6Cl2(g)→4PCl3(l)P4(s)+6Cl2(g)→4PCl3(l)A reaction mixture initially contains 45.35 gg P4P4 and 130.9 gg Cl2Cl2.       Once the reaction has reached completion, what mass (in gg) of the excess reactant is left?

What is the maximum mass of S8S8 that can be produced by combining 88.0 g88.0 g of each reactant?   8SO2+16H2S⟶3S8+16H2O   mass of S8:

What is the maximum mass of H₂O that can be produced by combining 69.7 g of each reactant? 4 NH3(g) + 5O₂(g) 4 NO(g) + 6H₂O(g)

My theoretical yield of beryllium chloride was 12.4 grams.  In an experiment, if my actual yield was 7.8 grams, what was my percent yield?   Be   +  2 HCl -----> BeCl2   +  H2