College Physics
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ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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What is the mass of water in a closed room 5.0m×6.0m×2.4m5.0m×6.0m×2.4m when the temperature is 25 ∘C∘C and the relative humidity is 73%?
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- Don't use chat gptarrow_forwardA large cylindrical coffee pot in a coffee shop filled with 10.0 kg of hot coffee at temperature T = 95.0 ° C rests on a wooden table. The steel pot has radius r = 8.00 cm and height h = 50.0 cm and an emissivity e = 0.600. See figure. Assume that all heat loss is radiative through the side and top of the pot, given that wood is a relatively poor thermal conductor. The coffee shop ambient temperature T = 20.0 ° C. a) Find the rate at which the coffee losses heat. b) Assuming constant heat loss rate, what is the coffee temperature after 10.0 minutes have elapsed? Cw = 4.19 x 103 J/kg °C, ρw = 1.00 x 103 kg/m3, σ = 5.67 x 10 -8 W/m2 K4arrow_forwardWhat is the cost of heating water in a swimming pool of radius 3.5 m and depth 1.3 m from 13 degress celcius to 27 degress Celcius. If the price of energy is $0.08/ KWh. The specific heat of water is 4186 J/Kg/Cdegrees and density of water is 1000 Kg/m^3. (Hint: Volume of cylinder is πr2h) A. $30.25 B. $65.15 C. $95.50 D. $25.25 E. $133arrow_forward
- An ordinary drinking glass is filled to the brim with 350 mL of water at 100.0 "C. If the temperature is decreased to 20.0 °C, then what volume of water could be added to the glass? The coefficient of volume expansion for glass is 27.0x108 (C)¹. The coefficient of volume expansion for water is 210 x 10-6 (C)1. 'n Gewone drinkglas is tot heelbo gevul met 350 mL water by 100.0 "C. Watter volume water kan by die glas gevoeg word indien die temperatuur tot 20.0 °C daal? Die volume uitsettingskoeffisiënt van glas is 27.0x 10- (C)¹. Die volume uitsettingskoeffisiënt van water is 210 x 108 (C)¹. Select one: O a. 5.12 mL 5.88 mL. Ob. O c. 9.23 mL O d. 0.756 mL Oe. 7.68 mLarrow_forwardThe following data are given for the pressure and temperature variation in air as a function of elevation: Elevation in [m] 0. Temperature in [°C]_pressure [atm] 28 1. 1000. 25 0.796 2000. 19 0.6314 3000. 12 0.4982 4000. 3 0.3905 5000. -1 0.3043 6000. 11 0.2356 You want to check if these measurements are correct. You are going to use a balloon and rise in the corresponding altitudes. If the balloon weighs 1000kg (all included, weight of yourself, equipment, inflated part etc) calculate the volume of inflated part of the balloon, so that the initial acceleration is 15m/s?. Assume that the balloon is a sphere and neglect the deflated part of the balloon as far as volume is concerned. Can you verify all measurements with this volume of the balloon? What kind of adjustments do you need to make in order to complete your mission?arrow_forwardwhile on break, Jorge is forced to give his I year old nephew a bath. Before leaving to a porty, his sister gives him o 10L (10,000 mL) tub to bath his nephew in. She also´ tells him that if the water in it isn't exactly 37°C his boby nephew will cry and urinate on him. If the water from the cold faucèt is 20'C and water from the hot faucet is 60°C, how many Kilograms of hot water does Jorge need to put in the tub? How many kilograms of čold water?arrow_forward
- An apartment has the dimensions 16 m by 8 m by 5 m. The temperature is 30°C, and the relative humidity is 51 percent. What is the total mass (in kg) of water vapor in the air in the apartment?arrow_forwardSuper Invar, an alloy of iron and nickel, is a strong material with a very low coefficient of thermal expansion (0.20×10^6 C∘). A 2.5 m long tabletop made of this alloy is used for sensitive laser measurements where extremely high tolerances are required.How much will this alloy table expand along its length if the temperature increases 6.0 C∘?How much will a 2.5m long table made of steel expand along its length if the temperature increases 6.0 C∘?arrow_forwardWhen the coefficient of linear expansion, a, and the temperature change, T-T, are large, a length L, of a solid substance expands in length to a(T, -T₂) L₁ = L₁e O L=L[1 + a(Tƒ– T;)]. ○ Ly=al (Ty-T). O L=L[1 + In(a(T₁-T))]. a(T, I₂ = ₁₂₁[ 1 + ª²(²₁-7)].arrow_forward
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