
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Please set up the answer the correct way. I am having a hard time with putting the units in the correct spots.

Transcribed Image Text:### Calculation of Mass in Grams of KBr for a Given Solution
#### Problem Statement:
What is the mass in **grams of KBr** in **0.400 L** of a **0.350 M** solution?
#### Input Section:
- **Starting Amount**: Input fields to enter the initial values. The left input field is for the initial volume in liters (L), and the right input field is for the initial molarity (M).
#### Calculation Section:
- **Add Factor**: Buttons to add factors to the calculation. For example, multiplication (x) and parentheses ( ).
- **Predefined Values**:
- 8.43 × 10²²
- 39.10
- 9.60 × 10^(-3)
- 5.47
- 0.350 (the molarity of the KBr solution)
- 0.140
- 7.09 × 10²⁰
- 16.7
- 1
- 136 (presumably the molar mass of KBr)
- 0.400 (the volume in liters)
- 1.18 × 10^(-3)
- 6.022 × 10²³ (Avogadro's number)
- 119
- **Units**:
- g KBr (grams of KBr)
- mol KBr (moles of KBr)
- L (liters)
- M KBr (molarity of KBr)
- g KBr/mol (grams per mole of KBr)
- mL (milliliters)
#### Output and Reset Section:
- **ANSWER**: Box to show the calculated answer.
- **RESET**: Button to reset the calculation.
### Example Calculation Steps:
1. **Calculate Moles of KBr**:
- Use the formula \( \text{Moles} = \text{Molarity} \times \text{Volume} \)
- Here, \( \text{Moles} = 0.350 \, M \times 0.400 \, L \)
- \( \text{Moles} = 0.140 \, \text{mol KBr} \)
2. **Convert Moles to Grams**:
- Use the molar mass of KBr
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