what is the limit of (cos(x))^4/x^2 as x approaches 0 from the positive side?

(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f' (3/2) = -sin(3pi/2) and f" (3л/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = cos(3pi/2) Use Q(x) to approximate cos(4.6). cos(4.6) cos(3pi/2)

Find f. f "(x) = 9 + cos x, f(0) = -1, f(71/2) = 0 f(x) =

Let f(x) = 2 cos5 X f'(x) =