Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- Q5: Design a PDA for accepting a language (0"1"0 | m, n-1} give the ID form as we explain in the lecture. Apply the string "00011000" on this PDA using ID transitions.arrow_forwardplease explain.arrow_forwardThe operation Perm(w), applied to a string w, is all strings that can be constructed by permuting the symbols of w in any order. For example, if w= 101, then Perm(w) is all strings with two l's and one 0, i.e., Perm(w) = {101, 110, 011). If L is a regular language, then Perm(L) is the union of Perm(w) taken over all w in L. For example, if L is the language L(0*1*), then Perm(L) is all strings of 0's and 1's, i.e., L((0+1)*). If L is regular, Perm(L) is sometimes regular, sometimes context-free but not regular, and sometimes not even context-free. Consider each of the following regular expressions R below, and decide whether Perm(L(R)) is regular, context- free, or neither: 1. (01)* 2.0*+1* 3. (012)* 4. (01+2)* a) Perm(L(0*+1*)) is context-free but not regular. O b) Perm(L((01+2)*)) is context-free but not regular. c) Perm(L((01+2)*)) is not context-free. O d) Perm(L((01)*)) is regular.arrow_forward
- Computer Science You must count the number of strings of length 6 over the alphabet A = {x, y, z}. Any string of length 6 can be considered as a 6-tuple. For example, the string xyzy can be represented by the tuple (x,y,z,y). So the number of strings of length 6 over A equals the number of 6-tuples over A, which by product rule is N. Find N. (Use the following product rule for any finite set A and any natural number n : |A^n|=|A|^n)arrow_forwardLongest Common Subsequence:ExampleLCS for input Sequences “ABCDGH” and “AEDFHR” is “ADH” of length 3.LCS for input Sequences “AGGTAB” and “GXTXAYB” is “GTAB” of length 4.Implementation in Java.arrow_forwardA cyclic permutation of a string takes the string and shifts each letter forward by a constant amount k, with letters that shift off the end of the string coming back in at the front. For instance, the cyclic permutations of the string ABCDEF are FABCDE, EFABCD, DEFABC, CDEFAB, BCDEFA, and ABCDEF itself. A reverse cyclic permutation is the reverse of a cyclic permutation; for instance ABCDEF has the reverse cyclic permutation DCBAFE amongst others. Given two strings S and S", provide a linear time algorithm to decide whether S is a reverse cyclic permutation of S'.arrow_forward
- If we are given with the two strings we have to find the longest common sub-sequence present in both of them.ExampleLCS for input Sequences “ABCDGH” and “AEDFHR” is “ADH” of length 3.LCS for input Sequences “AGGTAB” and “GXTXAYB” is “GTAB” of length 4.Implementation in Javaarrow_forwardWrite a small piece of pseudo-code for generating a histogram H[L] for an intensity image I[YDIM][XDIM], where L is the total level of intensities of the image, H is the histogram array, XDIM * YDIM are the size of the image, and I[i][j] is the intensity value of the pixel at location (i,j), with i = 1, …, YDIM, and j = 1,…, XDIM. You might choose to use a certain program language that you are familiar with to write the code. You don’t have to compile the code.arrow_forwardQ6. Let B = {(M) M is a DFA that doesn't accept any string containing an even number of Os}. Show that B is decidable.arrow_forward
- Given the following CFG S → OB A → 1AA|A B → OAA The following strings can be generated except i. 001 ii. 000 iii.0011 iv. 01 O A. i and iii O B. i and ii O C. iv only O D. ii onlyarrow_forwardWrite a program in C that, given two points on a two-dimensional graph, outputs a message (string) if the line that connects them is horizontal or vertical, or if the slope is positive or negative.What would you modify or adjust in your code if we move from a 2D cartesian system to a 3D dimensional cartesian system?You need to take into consideration if the system is 3D and therefore you need to ask the user to insert X, Y , and Z.arrow_forward2.arrow_forward
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