What is the equivalent capacitance of 8 equal 400 nF capacitors in series? ○ 5 nF ○ 3200 nF ○ 32 nF ○ 50 nF

Find the following. (In the figure use C1 = 37.80 µF and C2 = 31.80 µF.)   (a) the equivalent capacitance of the capacitors in the figure above µF(b) the charge on each capacitor on the right 37.80 µF capacitor  µC on the left 37.80 µF capacitor  µC on the 31.80 µF capacitor  µC on the 6.00 µF capacitor  µC (c) the potential difference across each capacitor on the right 37.80 µF capacitor  V on the left 37.80 µF capacitor  V on the 31.80 µF capacitor  V on the 6.00 µF capacitor  V

The 40.0-μF capacitor is charged to 80.0 µC when the switch is open. The other capacitors have no charge. Find the charge and voltage on each capacitor after the switch is closed. S 40.0 μF 10.0 uF 14.0 μF 15.0 μF

Useful constants:   k=9.00×109 N.m2/C2   ε0= 8.85×10-12 C2/N.m2   µ0=4π×10-7 T.m/A   mp=1.67×10-27 kg   me=9.11×10-31 kg   e=1.6×10-19 C   g=10.0 m/s2

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For the figure bellow, the equivalent capacitance in µF is 20 uF 60 uF 100 uF 10 V 40 uF

AC1=7 µF capacitor, a C2= 3C 1 µF capacitor, and a C3= 9C1 HF capacitor are connected in series. A AV=8 V battery is connected across this combination. What is the potential difference across the C 3 capacitor? (Your result must be in units of volts and include 3 digit after the decimal point. Maximum of 3% of error is accepted in you answer.) 時 Av C1 C2 C3

Potential difference against the two capacitors in parallel is O v1 V2

You have two capacitors connected in parallel with values of 8 μF and 7 μF. What is their equivalent capacitance? 3.7 μF I don't know. 15 μF 0.27 μF

If a voltage source of 24.0 V is connected from top to bottom, what is the charge accumulated on the 3.5 µF capacitor, in µC, when fully charged?