Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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**Problem Statement:**

What is the equivalent capacitance between nodes \( a \) and \( b \)?

**Diagram:**

The diagram shows two capacitors connected in parallel between two nodes, \( a \) and \( b \). 

- The first capacitor has a capacitance of \( 3 \, \text{mF} \).
- The second capacitor has a capacitance of \( 6 \, \text{mF} \).

**Options:**

- \( 4.5 \, \text{mF} \)
- \( 9.0 \, \text{mF} \)
- \( 7.5 \, \text{mF} \)
- \( 2.0 \, \text{mF} \)

**Explanation:**

To find the equivalent capacitance \( C_{\text{eq}} \) for capacitors in parallel, use the formula:

\[ C_{\text{eq}} = C_1 + C_2 \]

Substituting the given values:

\[ C_{\text{eq}} = 3 \, \text{mF} + 6 \, \text{mF} = 9 \, \text{mF} \]

Thus, the equivalent capacitance between nodes \( a \) and \( b \) is \( 9.0 \, \text{mF} \).
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Transcribed Image Text:**Problem Statement:** What is the equivalent capacitance between nodes \( a \) and \( b \)? **Diagram:** The diagram shows two capacitors connected in parallel between two nodes, \( a \) and \( b \). - The first capacitor has a capacitance of \( 3 \, \text{mF} \). - The second capacitor has a capacitance of \( 6 \, \text{mF} \). **Options:** - \( 4.5 \, \text{mF} \) - \( 9.0 \, \text{mF} \) - \( 7.5 \, \text{mF} \) - \( 2.0 \, \text{mF} \) **Explanation:** To find the equivalent capacitance \( C_{\text{eq}} \) for capacitors in parallel, use the formula: \[ C_{\text{eq}} = C_1 + C_2 \] Substituting the given values: \[ C_{\text{eq}} = 3 \, \text{mF} + 6 \, \text{mF} = 9 \, \text{mF} \] Thus, the equivalent capacitance between nodes \( a \) and \( b \) is \( 9.0 \, \text{mF} \).
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