what is the empirical formula of a compound found to contain 52.13 % carbon, 13.15 % hydrogen, and 34.72 % oxygen by mass

Given : Mass percent of C = 52.13 %

Mass percent of H = 13.15 % 

And mass percent of O = 34.72 %

Assuming the total mass of compound is 100 g and empirical formula of the compound is C_aH_bO_c.

The mass of elements in the compound is given by 

$$\begin{gathered} Mass of C = \frac{Mass of compound X mass percent of C}{100}= \frac{100 X 52.13}{100}= 52.13 g \\ Mass of H = \frac{Mass of compound X mass percent of H}{100}= \frac{100 X 13.15}{100}= 13.15 g \\ Mass of O = \frac{Mass of compound X mass percent of O}{100}= \frac{100 X 34.72}{100}= 34.72 g \end{gathered}$$