What is the electric field vector at the point where charge q₂ is located due to charges q₁ and q₃? (Hint: q₂ has no effect on the electric field on the point where it is located.) a. -8.640x10⁶ N/C ? - 1.152x10⁷ N/C j b. -1.728x10⁷ N/C ? - 2.304x10⁷ N/C j c. -8.364x10⁷ N/C ? - 2.396x10⁷ N/C j d. -1.296x10⁷ N/C ? - 1.728x10⁷ N/C j What is the electric potential at the point where charge q₂ is located due to charges q₁ and q₃? (Hint: q₂ has no effect on the electric potential on the point where it is located.) a. -180 000 V b. 360 000 V c. 0 V d. 180 000 V What is the electric potential at the point where charge q₃ is located due to charges q₁ and q₂? (Hint: q₃ has no effect on the electric potential on the point where it is located.) a. 0 V b. 180 000 V c. 360 000 V d. -540 000 V

What is the electric field vector at the point where charge q₂ is located due to charges q₁ and q₃? (Hint: q₂ has no effect on the electric field on the point where it is located.) a. -8.640x10⁶ N/C ? - 1.152x10⁷ N/C j b. -1.728x10⁷ N/C ? - 2.304x10⁷ N/C j c. -8.364x10⁷ N/C ? - 2.396x10⁷ N/C j d. -1.296x10⁷ N/C ? - 1.728x10⁷ N/C j What is the electric potential at the point where charge q₂ is located due to charges q₁ and q₃? (Hint: q₂ has no effect on the electric potential on the point where it is located.) a. -180 000 V b. 360 000 V c. 0 V d. 180 000 V What is the electric potential at the point where charge q₃ is located due to charges q₁ and q₂? (Hint: q₃ has no effect on the electric potential on the point where it is located.) a. 0 V b. 180 000 V c. 360 000 V d. -540 000 V

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 80AP: A 10cm10cm piece of aluminum foil of 0.1 mm thickness has a charge of that spreads on both wide side...

See similar textbooks

Similar questions

A circular ring of radius 23.0 cm has a continuous charge distribution of -1.4 C/m. How many excess electrons are on the ring? Write your result as multiplicative of 1018. Your result must contain one figure after the decimal point. Maximum of 3% of error is accepted in your answer. One electron charge is -1.6x10 19 C.
A change of -84 μC is placed in a uniform electric field that is directed vertially upwards with a feild strength of 8.63×104 N/C . The charge moves 1.40 mm at an angle of 30∘∘ doward from the horizontal (as shown below).
Given a charge Q1=50nC located at the XY coordinates (5m, 10m) and a charge Q2= -20nC located at the X, coordinates (-3m.-1m). The field point has coordinates (-3m, 4m). Find the Total Efield?
.00 44E0 Give an expression for the electric field strength E at a point in terms of the charge q and distance r from the charge to that point. Use k for k = 47). Flag question (i.e. Use the following notation (without the quotes): "/" for division, "*" for multiplication, "+" an "-" as usual. For powers used "^2", while for square root use "sqrt". To indicate that square root applies to the whole expression use brackets - for example, for √AB use sqrt(A*B). For Greek letters such as π, a etc. use pi, alpha. For example to get 1 AVAB use 1/pi* A^2/B*sqrt(AB). Please use the exact variables given in the conditions of the problem: e.gif L is given, then do not use 1. Please use "Display response" button to check the you entered correct expression, before submitting your answer. л в
A raindrop with charge q= +4 x 10 10 Cis suspended in the air a few cm above a very large plane of charge with density a it the mass of the raindrop is 12 mg find the charge density of the plane. (Take g 10 m/s and eoN9x 10 12 /N. m) Answer: 3. ++ +++
Charges q1 and q2 are located on the corners of a rectangle. If width w = 60 cm and length I = 80.2 cm find %3D the magnitude of the electric field (in N/C) at P when q1 = 4.08 nC and q2 = 1.43 nC. Round your answer to 1 decimal place.
help with the following and make sure its correct 100% before uploading pls and thank you ( also the ans of 12.66 m was wrong) Q: A point charge -5 q� is held fixed at the origin, and a second charge +q� is held fixed at x� = 8.0 mm. Where is the net electric field of these two charges zero? Express your answer with appropriate units.
An α - particle has mass of m = 6.64 x 10-27 kg and charge q = +2e (e = 1.60 x 10-19 C). Find the magnitude of the electric repulsion between two α - particle at 4.0 cm. Write your answer in decimal with 2 - significant figure. No unit required.
a total charge of 6.3x10^-8 is distributed uniformly throughout a 2.7 radius sphere. Thee volume charge density is: Answer: 7.6x10^-4c/m^3
This is an approximate model of a water molecule. Point charges q1 and q2 of -1.00 x 10-19 C and 1.00 x 10-19 C, respectively, are placed 0.600 x 10-12 m apart. Thus d = 0.300 x 10-12 m in fig. 2 below, D= 0.600 x 10-12 m At point b, what must be the y-component Eynet of the net electric field due to the two charges? Show work. At point b, what is the x-component Exnet of the net electric field due to the two charges? At point b, what is the direction of the net electric field due to the two charges? Indicate this direction by drawing an arrow in fig. 2 with its tail at point b. At point b, what is the magnitude of the net electric field due to the two charges? What is the relationship between your answer here and your answer to part (e)?
Problem 1: A spherical conductor is known to have a radius and a total charge of 10 cm and 20uC. If points A and B are 15 cm and 5 cm from the center of the conductor, respectively. If a test charge, q = 25mC, is to be moved from A to B, determine the following: What isThe work done in moving the test charge;
1 C of charge are placed on a spherical conducting shell. A particle with a charge of -4 C is placed at the center of the cavity. Find the net charge on the Inner surface of the shell. Express your answer in units of C with no decimal place. Do not forget the minus sign if your anwer is negative. ction will save this response Question 3 of 5