What is the electric charge, in the unit of μC, stored in a capacitor with C = 42 μF if the voltage across the capacitor is 1.6 V

A parallel plate capacitor with air between its plates is charged to 86.6 V and then disconnected from the battery. When an unknown dielectric material is placed between the plates, the voltage across the capacitor drops to 21.519 V. What is the dielectric constant of the unknown material? Assume that the material fills the space between the plates completely. Round your answer to 2 decimal places.

A parallel-plate air capacitor of area A = 10.5 cm2 and plate separation of d = 3.60 mm is charged by a battery to a voltage of 51.0 V. What is the charge on the capacitor?

A parallel plate capacitor has a charge of 0.0280 μC on each plate with a potential difference of 240 V. The parallel plates are separated by 0.400 mm of air. What energy is stored in this capacitor? Answer in μJ.

An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 2.10 mm. The capacitor is connected to a(n) 11.0 V battery. (a) Find the value of its capacitance. X PF (b) What is the charge on the capacitor? X pC

please answer v

The capacitance of an empty capacitor is 1.2 μF. The capacitor is connected to a 12-V battery and charged up. With the capacitor connected to the battery, a slab of dielectric material is inserted between the plates. As a result, 2.6 × 10–5 C of additional charge flows from one plate, through the battery, and onto the other plate. What is the dielectric constant of the material?