What is the ∆G° and equilibrium constant at 298 K for the following reaction? 2Cl2(g) + SO2(g)  SOCl2(g) + Cl2O(g) Substance ∆H°(kJ/mol) ∆S°(J/K mol) Cl2(g) 0 223.0 SO2(g) -296.8 248.1 SOCl2(g) -212.5 309.8 Cl2O(g) 80.3 266.1

Q: For propane, the ∆H° of vaporization is 22.90 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: Step 1: Step 2: Step 3: Step 4:

Q: What is ∆G° for the reaction CaO(s) + CO₂(g) → CaCO₃(s)

A: Standard Gibbs energy formation (∆fG0) of a compound is the Gibbs energy change accompanying the…

Q: Determine ∆G° for the reaction 3 N₂(g) + 2 O₃(g) → 6 NO(g) at 223°C.   ∆H°= +257.7 kj/mol ∆S°=…

A: Gibbs Free energy (G) : The energy associated with a chemical reaction that can be used to do work.…

Q: What is the equilibrium constant, K, for a reaction if ∆G° = -51.2 kJ/mol at 25.0 °C? (R = 8.314…

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Q: Determine ∆G° for a reaction when ∆G = -126.1 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol ･ K)

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Q: Calculate ∆H°, ∆S° and ∆G° at 298.15 K for the reaction H2 (g)+F2 (g)→2HF(g)

A: We know , Substance  ∆H°(kj/mol) ∆S° (j/mol K) ∆G° (kj/mol) H2(g) 0 130.58 0 F2(g) 0 202.7 0…

Q: What is ∆G° for the reaction CaO(s) + CO₂(g) → CaCO₃(s)?

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Q: Consider the reaction 3 CH41g2 ¡ C3H81g2 + 2 H21g2. Calculate ∆G at 298 K if the reaction mixture…

A: Our reaction is: 3CH4 (g)     ----->    C3H8 (g) + 2H2 (g)

Q: Determine the ∆G for 2N2H4(g) + 2NO2(g)  3N2(g) + 4H2O(g)at 25℃, if the initial partial pressures…

A: A balanced equation representing reaction between N2H4 and NO2 that gives N2 and H2O.

Q: Thermodynamics Quantities for Selected Substances at 298.15 K (25⁰C) Substance ∆H⁰f…

A: The degree of randomness in a system is measured in terms of entropy. The higher the entropy greater…

Q: Calculate the ∆G⁰reax value for the following reaction at 298K.CO (g) + ½ O2 (g) ↔ CO2 (g) Assuming…

A: Given, Temperature is 500 K We have to find the value of ∆G⁰reax. We will use the formula ∆G⁰reax =…

Q: Calculate the ∆G⁰reax value for the following reaction running at 298K. CO (g) + ½ O2 (g) ↔ CO2 (g)…

A: The given chemical equation as follows --- CO (g)   +    ½ O2 (g)    ↔    CO2 (g)…

Q: At what temperature, in °C, is a certain reaction at equilibrium if ∆H = +84.2 kJ/mol and ∆S =…

A: ∆G = ∆H - T∆S Where , ∆G = Change in Gibbs free energy ∆H = Change in Enthalpy ∆S Change in Entropy…

Q: What is K for a reaction if ∆G° =-164.6 kJ/mol at 25 °C (or 298 K)? (R = 8.314 J/mol ･ K)

A: Thermodynamics can be defined as a branch of chemistry in which we deal with the study of work, heat…

Q: Why not? What factors relate to rate of reaction? Considering entropy as related to the number of…

A: The measure of the amount of energy that is usable in a system is known as the Gibbs free energy (G)…

Q: What is K for a reaction if ∆G° =-369.4 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A: 1- First converted ∆G°  unit kJmol-1 to Jmol-1  ∆G° = -369. 4 kJmol-1  We know that, 1kJ = 1000 J…

Q: For propane, the ∆H° of vaporization is 22.9 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: Given :-  ∆H° of vaporization = 22.9 kJ/mol  ∆S° of vaporization = 99.0 J/mol.K  T = 214.5 K  To be…

Q: For propane, the ∆H° of vaporization is 22.9 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

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Q: For benzene, the ∆H° of vaporization is 30.72 kJ/mol and the ∆S° of vaporization is 86.97 J/mol･K.…

A: Given: The ∆H° of vaporization for benzene = 30.72 kJ/mol  The ∆S° of vaporization = 86.97 J/mol･K…

Q: Consider the reaction: ICl(g) + Cl₂(g) → ICl₃(s). The ∆G(f)° of ICl(g) is -5.5 kJ/mol and the ∆G(f)°…

A: For the given reaction: ICl(g) + Cl₂(g) → ICl₃(s) ∆G(f)° [ ICl(g)] =-5.5 kJ/mol ∆G(f)° [ Cl₂(g) ] =0…

Q: For the following reaction 2NO₂(g) ⇌ N₂O₄(g) ∆H° = -58.02 kJ/mol and ∆S° = -176.6 J/mol･K. What is…

A: The reaction is –                    2NO2g ⇔N2O4g Pressure        0.2                0.2Qp…

Q: For benzene, the ∆H° of vaporization is 30.72 kJ/mol and the ∆S° of vaporization is 86.97 J/mol･K.…

A: Step 1: Step 2: Step 3: Step 4:

Q: What is K for a reaction if ∆G° =-195.9 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

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Q: What is ∆G° for the reaction I₂(g) → 2 I(g) at 25.0 °C if K = 6.1 x 10⁻²²? (R = 8.314 J/mol･K)

A: We are authorised to solve only one question at a time. Please post rest of the questions…

Q: What is T if Keq = 2x104? Suppose that ∆G°= -50kJ/mol, ∆H° = -80kJ/mol, ∆S° = -150J/mol K at 298 K.…

A: The details solution for this is provided below in attach image.

Q: An example of a reaction where ∆G = 0 is H2O(s)→H2O(l) @SATP any reaction that is over…

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Q: For propane, the ∆H° of vaporization is 22.90 kJ/mol and the ∆S° of vaporization is 99.0 J/mol･K. At…

A: Given: ∆H° is 22.90 kJ or 22900 J ∆S° is 99 J/mol. K Temperature is 208.5 K To find: ∆G° of…

Q: What is ∆G° for the reaction 3 O₂(g) → 2 O₃(g) at 25°C if K = 6.1 x 10⁻⁵⁸? (R = 8.314. J/mol ･ K)

A: Relation between ∆G0 and Equilibrium Constant a K is  ∆G0=-RTlnK where ∆G0 is Gibbs free energy  Ris…

Q: Calculate ∆G for the reaction given below if the partial pressure of NO2 is 0.212 atm and the…

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Q: What is K for a reaction if ∆G° =173.2 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A: Given, Standard gibbs free energy (∆G°) = 173.2 kJ/mol = 173.2 × 1000 J/mol = 173200 J/mol…

Q: Consider the reaction of reactants A and B in equilibrium with products C and D. Given the following…

A: The equilibrium constant is the ratio between the product of concentration of products to that of…

Q: For butane, the ∆H° of vaporization is 22.4 kJ/mol and the ∆S° of vaporization is 82.3 J/mol･K. At…

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Q: For the equilibrium A + B ⇌ C + D K was measured to be 1.51 × 10⁻² at 25°C and 55.0 at 600°C. What…

A: The entropy change is said to be the process that is used to determine the disorder or randomness of…

Q: For butane, the ∆H° of vaporization is 22.4 kJ/mol and the ∆S° of vaporization is 82.3 J/mol･K. At…

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Q: A reaction has a ∆Horx = −70 kJmol and an equilibrium constant K =2.4 × 102 at 500 K. What is ∆Sorx…

A:

Q: For butane, the ∆H° of vaporization is 22.4 kJ/mol and the ∆S° of vaporization is 82.3 J/mol･K. At…

A: Gibb's free energy is the maximum work that can be obtained at constant temperature and pressure.…

Q: What is K for a reaction if ∆G° =-171.1 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

A: Gibbs' free energy and equilibrium constant has the following relation ∆G0 =-RT lnKeqm Or, Keqm =…

Q: For the following reaction H₂(g) + I₂(g) ⇌ 2HI(g) ∆H° = -10.64 kJ/mol and ∆S° = 21.48 J/mol･K. What…

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Q: The equilibrium constant for a chemical reaction is Kc = 243 at 25°C. What is the standard free…

A: Given : Equilibrium constant, K = 243 And temperature = 25 oC

Q: At

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Q: What is K for a reaction if ∆G° =-364.8 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A: Given, Standard gibbs free energy (∆G°) = -364.8 kJ/mol = -364.8 × 1000 J/mol = -364800 J/mol…