Here are summary statistics for randomly selected weights of newborn girls: n= 150, x = 33.4 hg, s = 7.8 hg. Construct a confidence interval estimate of the mean. Use a98% confidence level. Are these results very different from the confidence interval 31.0 hg <µ< 36.6 hg with only 12 sample values, x= 33.8 hg, and s= 3.6 hg?What is the confidence interval for the population mean u?hghg (Round to one decimal place as needed)

Answered: What is the confidence interval for the…

Math

Statistics

What is the confidence interval for the population mean u? ng << hg (Round to one decimal place as needed)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: find a 95% confidence interval for population mean. Assume the standard deviation is 4.78in. Would…

A: Given: Sample size n = 50 sample mean = 15.57 population standard deviation s = 4.78

Q: Nex Construct a confidence interval for p1 - p2 at the given level of confidence. X1 = 35, n1 = 239,…

A: Given : x1 = 35 , n1 = 239 x2 = 33 , n2 = 308 Confidence level = 90% To find: 90% confidence…

Q: None

A: The question asks for the 95% confidence interval of heating an area if the wattage is 1500…

Q: 100 samples were obtained from a normal population with means ? = 50 and variance ? = 4. For each…

A: Given Population mean, μ=50 Population variance, σ2=4 Sample size, n=100

Q: Salaries of 45 college graduates who took statistics course in college have a mean of 67,900…

Q: Use technology to construct the confidence intervals for the population variance and the population…

Q: asing the sample size will increase the precision of estimation of the confidence interval on the…

A: Confidence Interval : Let x1,x2,x3,....xn be a random sample from the…

Q: Express the confidence interval (76.2%, 93.2%) in the form of p+E. % ± ae

A: Confidence interval=(76.2% , 93.2%)Upper limit=93.2%Lower limit=76.2%

Q: Construct the indicated confidence interval for the population mean it using the t-distribution.…

A: Confidence level c=0.90 Sample mean x¯=13.1 Sample standard deviation s=4.0 Sample size n=6

Q: Construct a confidence interval for p₁ - P2 at the given level of confidence. x₁ = 397, n₁ = 537, x2…

A: Given,x1 = 397, n1 = 537x2 = 449, n2 = 552Confidence level, C = 90%

Q: you want to obtain a sample to estimate a population mean. based on previous evidence, you believe…

Q: Construct the indicated confidence interval for the population mean u using the t-distribution.…

A: We have given that n=13 Xbar=14.3 S=0.79 C=0.90

Q: A population forms a normal distribution with a mean of 85 and a standard deviation of 24 for each…

A: We have given that X~N(μ, ?^2) μ=85 , ?=24 , n=144 , xbar =90

Q: other factors remaining unchanged, which of the following will increase the size ( the distance from…

A: Confidence interval: It is said to be a range of values that is primarily used to estimate the true…

Q: The mean gasoline consumption of 20 cars is 45 liters with standard deviation of 3 liters, and 95%…

A: The provided information is x¯=45n=20σ=3α=0.051.The point estimate of the population mean µ is b.45…

Q: I-The area in the right tail under the t – distribution curve for 90% confidence level and degree of…

A: Given, t -test is right tail. confidence level = 90% Degrees of freedom = 40 To find, The…

Q: Construct a confidence interval for P₁ P2 at the given level of confidence. x₁ =25, n₁ = 236, x₂ =…

A: given data n1 =236 x1 = 25p^1 = x1n1 = 25236 = 0.1059 n2 = 299 x2 = 36p^2 = x2n2 = 36299 =…

Q: A survey of 9 popular restaurants is used to estimate the mean number of kitchen employees. Which…

A: A survey of 9 popular restaurants is used to estimate the mean number of kitchen employees.

Q: Data on 4500 college graduates show that the mean time required to graduate with a bachelor's degree…

A: given;sample size(n) = 4500mean(x¯)=6.38 yearsstandard deviation(s) =1.39 yearsconfidence level 95%…

Q: Construct a confidence interval for p, - P2 at the given level of confidence. X, = 352, n, = 548, x,…

A: Given that Sample sizes n1=548 , n2=577 Favorable cases x1=352 , x2=423

Q: The confidence level for the upper confidence bound of the population mean with unknown standard…

A: Given: The sample is drawn from a normal population. The population standard deviation is unknown.…

Q: Construct a 90% confidence interval of the population proportion using the given information. x=…

Q: Suppose you want to do a confidence interval for the mean age of your clients when X has a normal…

A: Given that, Critical values: Using the z-table, the critical value at 95% confidence level is

Q: Construct a confidence interval for p₁ - p2 at the given level of confidence. x₁ = 386, n₁ = 525, x₂…

A: Sample 1: x1=386n1=525 Sample 2: x2=403n2=564 Confidence level=0.90

Q: What is the confidence interval for the population mean p? kg<u< kg (Round to one decimal place as…

Q: Consider a confidence interval, with confidence coefficient 1- a, for the mean of a normal…

A: here AS PER GUIDELINES I HAVE CALCULATED FIRST MAIN QUESTION , AS YOU POSTED SECOND QUESTION WHICH…

Q: estimate the mean time required to graduate for all college graduates. Also, find the 95% confidence…

A: Given: sample size(n)=4200sample meanx¯=5.44standard deviation(s)=1.88 Estimate for the mean time…

Q: The confidence level for the upper confidence bound of the populati with unknown standard deviation…

A: Let X be a random variable following normal distribution with mean μ and variance σ2, i.e.,…

Q: A mobile phone manufacturer wishes to estimate how frequently their customers buy a new phone. They…

A: Solution: Let X be the random variable. From the given information, x-bar=1.9 years, S=1.2 and n=22.

Q: give examples about point estimation (confidence interval)

A: Example on the basis of Point estimation

Q: Planning engineers want to construct a confidence interval for the standard deviation of the runtime…

Q: It is believed that the depth of a river is 15m and the SD = 1.6m An engineer believes that is too…

A: Given information Sample mean x̅ = 15.8 m Population mean µ = 15 m Sample size n = 33 Standard…

Q: Planning engineers want to construct a confidence interval for the standard deviation of the runtime…

A: We have given that, Sample mean (mu) = 220 and standard deviation (s) = 25 then, variance (s^2)=…

Q: Construct a confidence interval of the population proportion at the given level of confidence. x=…

Q: Construct a confidence interval for p1−p2 at the given level of confidence. x1=367, n1=508,…

Q: Using the given confidence interval to find the margin of error, Confidence interval (5.88,…

A: Answer: From the given data, given the Confidence interval is (5.88, 9.86)

Q: Construct the confidence interval for the population mean u. -0.90, x=4.3, o-0.3, and n-52 A 90%…

A: According to the given information, we havec=0.90x=4.3σ=0.3n=52

Q: SAT scores are distributed with a mean of 1,500 and a standard deviation of 300. You are interested…

A: compute sample size n = (z a/2 * s.d / me ) ^2z alpha/2 at 0.05 level of significance is = 1.96 (…

Q: 3- What is the confidence level for the interval it 1.47? vn

A: The confidence level for interval x±1.47σn is obtained as shown belowThe critical value of z is…

Q: An IQ test is designed so that the mean is 100 and the standard deviation is 21 for the population…

A: Mean = 100 Standard deviation = 21 95% confidence level

Q: Estimate population mean (σ is unknown): A sample of 25 novels has a mean of 12 and standard…

A: Mean = 12 Standard deviation = 9 Sample size = 25 89% confidence level

Q: Planning engineers want to construct a confidence interval for the standard deviation of the runtime…

A: Given: s2 = 1225352 nn = 2525

Q: Find the interval estimate for the mean of paired difference with 95% confidence level. (sd = 1.34)…

A: This is a problem of confidence interval for pair difference with significance level α=0.05.Here,…

Q: a baker makes cookies n= 50, mean = 10, s = 2. what is the lower bound for a 90% confidience…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Here are summary statistics for randomly selected weights of newborn girls: n= 150, x = 33.4 hg, s = 7.8 hg. Construct a confidence interval estimate of the mean. Use a
98% confidence level. Are these results very different from the confidence interval 31.0 hg <µ< 36.6 hg with only 12 sample values, x= 33.8 hg, and s= 3.6 hg?
What is the confidence interval for the population mean u?
hg
hg (Round to one decimal place as needed)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Construct a confidence interval for p, - p, at the given level of confidence. X1 = 398, n1 = 543, x2 = 408, n2 = 578, 99% confidence The researchers are % confident the difference between the two population proportions, p, - p2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
Which of these is NOT a way to express a confidence interval for the mean? (59.41, 81.72) 46.78 < x̄ < 62.90 42 ± 3.2 45.2 < μ < 63.7
Library From a sample of 23 graduate students, the mean number of months of work experience prior to entering an MBA program was 34.24. The national standard deviation is known to be 18 months. What is a 99% confidence interval for the population mean? Accessib A 99% confidence interval for the population mean is (Use ascending order. Round to two decimal places as needed.) Purchas Commu Enter your answer in the edit fields and then click Check Answer. All parts showing Clear All Check Answer ns Type here to search acer F6 F8 R
A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a 90.16% confidence interval. The blood cholesterol level of young men follows a Normal distribution with standard deviation σ = 15 mg/dl. How large a sample would the researcher need to take to estimate the mean blood cholesterol to within 7 mg/dl? A sample of at least______people
Construct a confidence interval for p, - P, at the given level of confidence. X1 = 34, n1 = 273, x2 = 32, n2 = 313, 90% confidence The researchers are % confident the difference between the two population proportions, p, - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
Help!
Construct a confidence interval for P₁-P₂ at the given level of confidence. X₁ = 369, n₁ = 508, X₂ = 426, n₂ = 599, 95% confidence % The researchers are confident the difference between the two population proportions, P₁-P₂, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
Construct a confidence interval for p1- P2 at the given level of confidence. x1 = 26, n1 = 270, x2 = 38, n2 = 296, 99% confidence The researchers are 1% confident the difference between the two population proportions, p1 - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
Construct a confidence interval for P₁ P2 at the given level of confidence. x₁ = 391, n₁ =529, x₂ = 421, n₂ = 577, 90% confidence The researchers are % confident the difference between the two population proportions, p₁ - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
USE 3 DECIMAL A researcher believes that reading habit of newspaper is decreasing every year. In order to see the true population proportion of people who are reading newspaper s/he collect a randomly selected people on the yearly basis. The following table gives the number of people who do not read newspaper with respect to the years. Construct a 90 % confidence interval for the true population proportion difference of people who are reading newspaper in 2005 and 2010. 20102005 n 12001000 Number of people who do not read newspaper 300 400
USE 3 DECIMAL A researcher believes that reading habit of newspaper is decreasing every year. In order to see the true population proportion of people who are reading newspaper s/he collect a randomly selected people on the yearly basis. The following table gives the number of people who do not read newspaper with respect to the years. Construct a 90 % confidence interval for the true population proportion difference of people who are reading newspaper in 2005 and 2010. 20102005 12001000 Number of people who do not read newspaper 900 700