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- a. In the absorption spectrum of the complex ion Cr(NCS)63, there is a band corresponding to the absorption of a photon of light with an energy of 1.75 104 cm-1. Given 1 cm1 = 1.986 1023 J, what is the wavelength of this photon? b. The CrNC bond angle in Cr(NCS)63 is predicted to be 180. What is the hybridization of the N atom in the Ncs- ligand when a Lewis acid-base reaction occurs between Cr3+ and NCs- that would give a 180 CrNC bond angle? Cr(NCS)63 undergoes substitution by ethylenediamine (en) according to the equation Cr(NCS)63+2enCr(NCS)2(en)2++4NCS Does Cr(NCS)2(en)2+ exhibit geometric isomerism? Does Cr(NCS)2(en)2+ exhibit optical isomerism?Two different compounds are known with the formula Pd(py)2Cl2, but there is only one compound with the formula Zn(py)2Cl2. The symbol py is for pyridine, a mono-dentate ligand. Explain the differences in the Pd and Zncompounds.Ammonia and potassium iodide solutions are added to an aqueous solution of Cr(NO3)3. A solid is isolated (compound A), and the following data are collected: i. When 0.105 g of compound A was strongly heated in excess 0 2, 0.0203 g CrO3 was formed. ii. In a second experiment it took 32.93 mL of 0.100 M HCI to titrate completely the NH3 present in 0.341 g compound A. iii. Compound A was found to contain 73.53% iodine by mass. iv. The freezing point of water was lowered by 0.64C when 0.601 g compound A was dissolved in 10.00 g H2O (Kf =1.86Ckg/mol). What is the formula of the compound? What is the structure of the complex ion present? (Hints: Cr3+ is expected to be sixcoordinate, with NH3 and possibly I as ligands. The I ions will be the counterions if needed.)
- A transition metal ion, M, forms a coloured complex with a monodentate ligand L. Portions of a 0.05 mol dm-³ solution of M are mixed with portions of a solution containing 0.05 mol dm-³ of L so that the total volume of the resulting mixture is always 10 cm³. The colour intensity of the complex in each mixture is measured using a colorimeter. The graph of the results is 0 1 2 3 3 4 5 6 7 8 9 10 cm³ of M 10 9 8 7 6 5 4 3 2 1 0 - cm³ of L What is the formula of the complex? A ML B ML₂ C ML₂ с D D ML4 Colour intensity 7:2Titanium and vanadium form colored complexes when treated with hydrogen peroxide in 1 M sulfuric acid. The titanium complex has an absorption maximum at 415 nm, and the vanadium complex has an absorption maximum at 455 nm. A 1.00 × 10−3 M solution of the titanium complex exhibits an absorbance of 0.816 at 415 nm and of 0.485 at 455 nm, while a 2.00 × 10−3 M solution of the vanadium complex exhibits absorbances of 0.425 and 0.608 at 415 and 455 nm, respectively. A 1.000-g sample of an alloy containing titanium and vanadium was dissolved, treated with excess hydrogen peroxide, and diluted to a final volume of 1000 mL. The absorbance of the solution was 0.697 at 415 nm and 0.533 at 455 nm. Calculate: a) The concentration of titanium and vanadium in the sample. b) The percentages of titanium and vanadium in theThe compound hexaamminecobalt(III) chloride is diamagnetic and orange in color with a single absorption peak in its visible absorption spectrum. What is the electron configuration of the cobalt(III) ion?
- Why does orbital mixing result in pale coloured transition metal complexes? Use diagrams to explain your answer.At 580 nm, the wavelength of its maximum absorption, the complex Fe(SCN)2+ has a molar absorptivity of 7.00x103 L mol-1 cm-1. Calculate letter D ONLY a.) the absorbance of 2.50x10-5 M solution of the complex at 580 nm in 1.00-cm cell. = 0.175 b.) the absorbance of a solution in which the concentration of the complex is twice that in part (a). c.) the transmittance of the solutions described in parts (a) and (b). d.) the absorbance of a solution that has half the transmittance of that described in part (a).Titanium(IV) and vanadium(V) form colored complexes when treated with hydrogen peroxide in 1 M sulfuric acid. The titanium complex has an absorption maximum at 415 nm, and the vanadium complex has an absorption maximum at 455 nm. A 1.00 x 103 M solution of the titanium complex exhibits an absorbance of 0.805 at 415 nm and of 0.465 at 455 nm, while a 1.00 x 10-2 M solution of the vanadium complex exhibits absorbances of 0.400 and 0.600 at 415 and 455 nm, respectively. A 1.000-g sample of an alloy containing titanium and vanadium was dissolved, treated with excess hydrogen peroxide, and diluted to a final volume of 100 mL. The absorbance of the solution was 0.685 at 415nm and 0.513 at 455nm. What were the percentages of titanium and vanadium in the alloy?
- An aqueous solution of a complex ion that has a maximum absorbance at 632 nm will appear... what color and why?Let’s consider octahedral Sc3+ and Ti3+ complexes. How many d electrons will each have? Sc3+: 0; Ti3+: 0 Sc3+: 0; Ti3+: 1 Sc3+: 1; Ti3+: 0 Sc3+: 1; Ti3+: 1Provide explanations for the number of intense perchlorate Cl-O stretching vibrational modes observed in the IR of the following three silver(I) complexes. explain briefly 1) The perchlorate anion in Ag(NH3)2(ClO4) has a single intense Cl-O stretching vibrational mode observed by IR at 1170cm-1. 2) The IR of Ag(NH3)ClO4 has three Cl-O stretching vibrational modes at 1220 cm-1,1130 cm-1and 920 cm-1 observed in the IR .