What is the best case, worst case time complexity for determining if a given directed edge exists in a graph. Assume the outgoing edges from each Vertex are stored in an adjacency list for that vertex. V is the total number of vertices in the graph, and E is the total number of outgoing edges in the graph, and you can find the vertex itself in constant time from a HashTable or HashMap ? Best Case: [ Select ] Worst Case: [ Select] /[ Select ] O(1) O(V) O(E) O(V+E)

CSE Python LAB: Question 2} You initially start with a binary string S0 which is of length N and has all 0s. You are then given U updates, which keep transforming the string. The i-th update transforms the string Si-1 into Si, and hence after all the U updates you will be left with SU. A single update is of the form (Li, Ri), which means that all the 1s in the range [Li, Ri] (both end points included) should be changed into 0s, and all the 0s in that range should be changed to 1s. You need to find out which among the U+1 binary strings: S0, S1, .., SU, is lexicographically the largest, and print that string. You have to develop a python program that output a single line containing one binary string Sample Input: 10 10 9 10 6 10 9 10 1 8 3 5 3 3 3 4 3 9 4 8 7 7 Sample Output: 1111100011

/*** Define string that prints correctly formatted multiplication table with* header and column prefix. Add --- and | delimiters between prefix and* table data** You may assume table has at least 1 row with 1 element** Use System.lineSeparator() to delimit individual lines** <pre>| 0, 1, 2, 3, 4, 5---------------------------0| 01| 0, 12| 0, 2, 43| 0, 3, 6, 94| 0, 4, 8, 12, 165| 0, 5, 10, 15, 20, 25* </pre>** @param table* 2D array of integers (not rectangular!)* @return String as formatted multiplication table*/public static String tableToString(int[][] table) {

1. Determine x[z] if [you use your ID as follows the first four numbers from right as x[n] and h[n] as the first five numbers from left respectively ] (for example If Your ID= [439804543]) then x[n] = {4, 3, 9, 8, 0₁, 4, 5, 4, 3}?