College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- What is the algebraic expression for the normal force on mass m1?
- Find an algebraic expression for the horizontal net force on mass m1. Use your answer from Part A for the normal force in the formula for the friction force. (Let right be the positive direction.)
- What is the algebraic expression for the normal force on mass m2?
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- Problem 5: Ablock with a mass of m rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction. The second acts on the body at an angle e measured from horizontal, as shown. If necessary, use Fs and Fk for the forces of static and kinetic friction. F m -F, Please use the interactive area below to draw the Free Body Diagram for this block, assuming it is in static equilibrium. 1 Add Force O Reset All m. Ftotal,x: Ftotal,y:arrow_forwardTwo blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one block with mass m1 = 12.25 kg is on a horizontal table and the other block with mass m2 = 7.5 kg hangs vertically. Both blocks experience gravity and the tension force, T. Use the coordinate system specified in the diagram. a.) Assuming friction forces are negligible, write an expression, using only the variables provided, for the acceleration that the block of mass m1 experiences in the x-direction. Your answer should involve the tension, T. b.) Under the same assumptions, write an expression for the acceleration, a2, the block of mass m2 experiences in the y-direction. Your answer should be in terms of the tension, T and m2. c.) Carefully consider how the accelerations a1 and a2 are related. Solve for the magnitude of the acceleration, a1, of the block of mass m1, in meters per square second. d.)Find the magnitude of the tension in the rope, T, in newtons.arrow_forwardPlease draw the free diagram clear and also indicate if we need to add forcearrow_forward
- Please do A-C, Thank you!arrow_forwardA 1500-kg barge is being towed by means of two horizontal cables. One cable is pulling with a force of 90.0 N in a direction 25.0° west of north. Assume that the water exerts no appreciable frictional drag on the barge. Determine the following, showing all your steps clearly: a. In what direction should the second cable pull so that the barge will accelerate northward, if the force exerted by the cable is 130 N? Give your answer as an angle relative to north and state which direction (east of north or west of north). b. What is the acceleration that the barge moves north with? c. How far does it move in the first 15 seconds?arrow_forwardA cabinet of mass 3.7 kg is at rest on a ramp as shown. What is the magnitude of the friction force on the cabinet, in Newtons? The coefficients of friction between the cabinet and ramp are Ps = 0.850 and uk = 0.750. Use g = 10 m/s2. (Hint: what type of friction is it?) Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. 30.0arrow_forward
- Consider the system in the picture below: a cart of mass M with a static friction coefficient u is connected through a massless string to a hanging mass m. M is a capital letter, m is lower case. Write them as such, or vour equations will be confusing, M We want to find the maximum value of the hanging mass m such that the system is in equilibrium. 1. Free body diagram (FBD): Draw a FBD for each: the Cart and the hanging mass. Clearly show all the forces. 2. Clearly write the equilibrium equations for the cart in the horizontal and vertical direction. 3. Clearly write the equilibrium equation for the hanging mass. 4. Solve the system of the three equations above for the hanging mass m. Show your calculation to get credit. 5. What would happen if mass m exceeds this value? Explain.arrow_forward9. If a passenger vehicle travels in a circular path at too high a speed, it can tip over. The image below shows a vehicle beginning to tip over. A group of students investigated the speed at which a passenger vehicle will begin to tip over by using a remote- control toy car. The students drove the car around circular paths of various known radii, at such a speed that it was just starting to tip for each radius. They timed the period of the cars motion and used the period to calculate the 'tipping speed' (the speed at which the toy car begins to tip over) of the car. The graph below shows the data collected by the students: Speed at which toy car begins to tip over (m s'¹') 14 12 10 8 TESTO 0 2 3 Radius (m) 5 6 7 Page 11arrow_forwardProblem 1: A block with a mass of m rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction. The second acts on the body at an angle 0 measured from horizontal, as shown. If necessary, use Fs and Fk for the forces of static and kinetic friction. L. F Please use the interactive area below to draw the Free Body Diagram for this block, assuming it is in static equilibrium. FBD : Fn, F1, Fg, F2, Fs, Fk, a, v 45, 0, 90, 135, 180, 225, 270, 315, 0 Force Labels: Angle Labels: m.arrow_forward
- The previous step focused on friction for horizontal surfaces. As we discussed above, angled surfaces like the wedge below have different considerations. FN = mg cos(0) F₁ = mg F₁ = ? F₁ = ? Fy=mg cos(0) Specifically, we have the following considerations. 1. The normal force is not equal to mg. 2. There is a force acting along the angle of the wedge due to gravity. What is the coefficient of static friction ? Fx = mg sin(0) Let's consider the implications of this type of problem with the following examples. For all of the examples, the box has a mass of 25 kg. Imagine the box is on a surface that allows you to adjust the incline angle, 0. You find the maximum angle where the box remains stationary. That is, at any higher angle, and the box begins to slide. The static friction force at this maximum angle is 150 N. What is the angle 0 (in degrees)? Now you raise the incline to an angle of 60° greater than the angle of maximum static friction found above. At this angle, the box slides…arrow_forwardA man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle 0. Described how the force components (Fx,Fy) change as the angle increases from 0 degrees to 90 degrees and use your graph to explain your answer. Give a detailed explanation of the forces at 0= 0, 45degrees, and 90 degrees. please show a sample calculation at one angle for both components. arrow_forward
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