What is the AH° for the following reaction: H2O (1) + CH4 (g) --> CH;OH (I) + H2 (g) Given the AHf for the following compounds: AHf Compounds (kJ/mol) H2O (I) -285.8 H2O (g) -241.8 CH4 (g) -74.6 C2H6 (g) -84.0 CH3OH (I) -239.2 CH3OH (g) -201.0

Use the AH, information provided to calculate AH for the following: > SO,Cllg) + 2 H2O() AH, J/mol) 2 HCIG)+ H,S04) AH n 50,Cylg) -364 H,O -286 HCG) -92 H2SO -814 62 kJ 0-256 kJ 422 kJ O 256 kJ O -62 kJ

H2 (g) + Cl2 (g) –→ 2 HCI (g) Using the following information, calculate AHrxn for the reaction above: NH3 (g) + HCI (g) → NH,CI (s) AHxn = -176 kJ/mol N2 (g) + 4 H2 (9) + Cl2 (g) → 2 NH,CI (s) AHxn = -628 kJ/mol | NH3 (g) → 1/2 N2 (g) + 3/2 H2 (g) AHxn= 46 kJ/mol number or fraction only kJ/mol

Calculate the AH°rxn for the combustion of methane using the given AH°r. CH4 (g) + 202 (g) 2H20 (1) + CO2{g) AH°t, methane(g) = -74.60 kJ/mol AH°f, water(l) = -285.8 kJ/mol AH°t, carbon dioxide(g) = -393.5 kJ/mol 890.5 kJ/mol -890.5 kJ/mol -1.04 x 103 kJ/mol