A sample of 100 grade 10 students age was obtained to estimate the mean of all grade 10 students. Given x = 15.3 years and the population variance is 16 What is the 95% confidence interval for u14.06-16.49414.15-16.34514.423-16.10714.516-16.084What is the 99% confidence interval for u?14.424-15.95814.27-16.3314.423-16.10714.06-16.494

Name: A sample of 100 grade 10 students age was obtained to estimate the mea
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A sample of 100 grade 10 students age was obtained to estimate the mean of all grade 10 students. Given x = 15.3 years and the population variance is 16 What is the 95% confidence interval for u14.06-16.49414.15-16.34514.423-16.10714.516-16.084What i

Answered: What is the 95% confidence interval for…

Math

Probability

What is the 95% confidence interval for u 14.06-16.494 14.15-16.345 14.423-16.107 14.516-16.084 What is the 99% confidence interval for u? 14.424-15.958 14.27-16.33 14.423-16.107 14.06-16.494

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

If no data values are given but the mean and standard deviation is given how do I find the variance with just this information?
Birth weight at a local hospital for the past year had a normal distribution with a mean of 106 ounces and a variance of 36 ounces2. If the middle 50% of the birth weights are considered to have a normal birth weight then what is the birthweight that defines a high birthweight baby (above normal)?
A man measures his heart rate before using a treadmill and then after walking ona treadmill for 10 minutes on 7 separate days. His mean heart rate at baseline and10 minutes after treadmill walking is 85 and 93 beats per minute (bpm), respectively. The mean change from baseline to 10 minutes is 8 bpm with a standarddeviation of 6 bpm.(a) What test can we use to compare pre- and post-treadmill heart rate?(b) Implement the test in 2a, and report a two-tailedp-value.(c) Provide a 90% confidence interval (CI) for the mean change in heart rate afterusing the treadmill for 10 minutes.(d) What is your overall conclusion concerning the data? this is a review question of ch8 bernard rosner. the solution is not provided at bartleby for this review question
A sample has a minimum value of 7 and a maximum value of 58 .Estimate its variance.
For what types of data do we use chi-square tests?
Suppose the scatter diagram of a random sample of data pairs (x,y) shows no linear relationship between x and y. Do you expect the value of the sample correlation coefficient r to be close to 1, -1,or 0?
Mr Chimbukutu, owner of a bakery said that the average weekly production level of his company was 11,398 loaves and the variance is 49,729. If data used to compute the results were collected for 32 weeks, during how many weeks was the production level below 11,175 and above 11,844?
Given that age of ECU students is normally distributed. A random sample of 16 students had an average age of 25 years and a variance of 4 square years. The 98% CI for the true average age of all ECU students is?
Suppose that the variance of the sample mean is equals 25 and the sample size is 6 . then the population variance is
7.Which of the values below is closest to the IQR for a normally distributed population with a variance of 36? chosse one: 5,6,7,8,9
a sample of n = 10 score has ss= 108 what is the variance for this sample
Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…