What is meant by a nitric acid is being a strong acid?   a. HNO3 does not dissociate at all when it is dissolved in water. b. Aqueous solutions of  HNO3 contain equal concentrations of H+(aq) and OH-(aq). c. HNO3 cannot be neutralized by a weak base. d. HNO3produces a gaseous product when it is neutralized. e. HNO3 dissociates completely to H+(aq) and NO3-(aq) when it dissolves in water.

3. Which of these is the active ingredient in vinegar? A. calcium hydroxide B. sulfuric acid C. phosphoric acid D. ammonium phosphate E. acetic acid

HF reacts with OH, resulting in F and H₂O. Which statement is true? HF is an acid because it donates a proton HF is an acid because it accepts a proton OH is an acid because it donates a proton OH is an acid because it accepts a proton

5. Which compound is an Arrheni us acid? A HSO, R KCI C. NaOH D. NH,

It takes 18 ml of a 0.01 M standard solution of KOH to neutralize 50 ml of a HBr solution of unknown concentration. What is the concentration of the HBr solution?

E' E a. a. C6H5NH2 (aq) + H₂O (l) C6H5NH3* (aq) + OH- (aq) When you measure the concentrations of the ionized substances you find them to be: [C6H5NH₂] = 0.234 mol/L [C6H5NH3*] = 2.8 x 10-5 mol/L [OH-]= 2.8 x 10¹5 mol/L If the Kb is 4.27 x 10-10, is the reaction at equilibrium? If not, which direction does it need to move (right or left) to reach equilibrium? Explain. At equilibrium the concentrations of the ionized substances are: [C6H5NH₂] = 0.0537 mol/L [C6H5NH3*] = 4.79 x 10¹ mol/L [OH-]= 4.79 x 10-6 mol/L If this reaction is taking place in a 2.0L container, and 1.5 moles of phenylamine were added to the reaction, what will the new concentrations of the three ionic species be when equilibrium is re-established? CoHsNHz(aq) + H₂O (l) 2. Determine the K₂ for the above solutior 3. Determine the pH for the above solution 누 C6H5NH3+ (aq) + OH- (aq)

The concentration of hydroxide ion in an aqueous solution at 25°C is 7.2 x 10-4 M. What is the concentration of the hydronium ion? 1 2 3 4 6. C 7 8 9. +/- x 100 +

d. HCl (1 eq) e. + O