
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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16-12 What force F can be applied to the system shown in the figure, governed by the 25 X 16-mm aluminum-alloy bar AB? The factor of safety on the Euler buckling load is to be 2.5. Assume the ends are pinned. E = 70 GPa.

Transcribed Image Text:Rod
B
Bar
400 mm
A
300
Fig. P16-12
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- If F=1kN,the magnitude of the vertical reaction force developed at the point B?arrow_forwardProblem 2 Assume that Member AB may be considered as long and slender and consider only Euler buckling. What is the critical Euler buckling load and will Member AB buckle? What is the factor of safety of the compressive load with respect to the critical buckling load? Assume buckling only occurs in the plane of the paper. Note: E-30e6psi, I-6.36e-3 in', A-2.83 in², LAB-41.6 in, FAB-540 lb (compression). Also Member OB is 36 inches (3 ft) long. F=270 lbf 3 ft 3 60 A = 45270 LB, n = 83.8, buckles 48400 LB, n = A. Per B. Per C. Per = 1088 LB, n 897, does not buckle 2.02, does not buckle D. Per = 544 LB, n = 0.993, buckles E. None of Thesearrow_forwardConsider the steel truss and member cross-section presented in figures below. All the members of the truss have the same cross-section as shown in the figure to the right. They all also have a Young's Modulus of 210 GPa. What can the highest value of force F be before member AC fails by buckling? Force 1AN - 300 mm 40° 4 m $35 mm 7m 300 mm 8 m 35 mm 35 mm 35 mm Please provide your answer in kN.arrow_forward
- Derive the Euler Buckling formula for column having fixed support at both ends. (eXPLAIN IN DETAIL IN HAND WRITTEN )arrow_forwardConsider two types of a column cross-section: a hollow square and a hollow circular section. In both cases the wall thickness is 6 mm and the area occupied by the load-bearing material is 965 mm². Find which of these two column types produces a better buckling performance with relevant calculations supporting your answer. Answer The outer size of the hollow square section can be calculated as mm • The outer diameter of the hollow circular section can be calcualted as . mm The second moment of area for the hollow square section can be calculated as mm The second moment of area for the hollow circle section can be calculated as mm Find which of these two column types produces a better buckling performance. O Hollow Circular Section O Hollow Square Sectionarrow_forward2" Problem 5: For the component shown in the figure. Where is the critical location? What steel do you recommend based on yielding and factor of safety n=3. (F=1000 lb) == 24243,936N Paper Buckling => (5,00016) (1125/2) J 1/64 (1125/9 = 26075,95 1.25" r = 0.06" F 51 Per = ('T ES 02 2F T = 5F lb - in 3350 72518.87 86000 = 98.99) ² 2n, 3arrow_forward
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