What features of the distribution in the histogram iet you know that modeling with a nornal distribution is reasonable? Model the simulations using a normal distribution with a mcan of 0.028 and a standard deviation of 1.124, What is the area under this nomal curve that is more extreme than 37
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- Data with 1,000 observations are drawn from a bell-shaped distribution with a mean of 85 and a standard deviation of 15. Approximately how many observations are more than 115? (Round your answer to the nearest whole number.)Birth weight s of newborns at a hospital have a normal distribution with a mean of 110 oz. and a standard deviation of 15 oz. A) What is the percentile if a newborn is about 120 oz?(show work) B) What birth weight does a newborn baby have to be in the upper 2.5%?(show work)Question 8 Using the standard normal distribution, find the two z-scores that that form the middle shaded region. The shaded region is symmetric about z = 0. Round your z-scores to two decimal places. Shaded Area = 0.22 4 -3 -2 -1 Negative z-score = Positive z-score = Submit Question APR 19 W
- Tech Worx magazine reported that91%of software engineers rate the company they work for as "a good place to work." You are a headhunter, and as such you state that the percentage in the report is not correct. In a survey of220randomly selected software engineers, 207rated the company they work for as "a good place to work." Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the significance level of0.05, to support his claim that the ratio,p, of all software engineers who rate the company they work for as "a good place to work" is not91%. (to) Formulate the null hypothesish and the alternative hypothesish that you will use in your test. ho: 0 h₁:0 Р np= n61-p) = (c) carry out aZ -testand find thep-value. OI am unsure of my answers for the histograms and I don't understand the empirical rule. Please explain the empirical rule and confirm my answers for the histogram question of my exercise is correct. Thank you.why Z=1.8 not 1.08? please draw a graph explain more detail?cmarks Window Help A ccco.desire2learn.com Home Community - CCA (25) D2L. Module 4 Test - MAT120C03 Math. • Search Results - Films On Demand Question 9 For a standard normal distribution, find: P(z Next QuestionA company that manufactures batteries used in electric cars is reporting that their newest model of battery has a mean lifetime, µ, of 18 years. To test the company's claim, a competitor has selected 56 of these batteries at random. The mean lifetime of the sample is 18.9 years. Suppose the population standard deviation of these lifetimes is known to be 4.8 years. Is there enough evidence to reject the claim that the mean lifetime of the newest model is 18 years? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H,. Ho: 0 OSolve this question pleaseSome students paid a private tutor to help them improve their results on a certain mathematical test. These students had a mean change in score of + 18 points, with a standard deviation of 68 points. In a random sample of 100 students who pay a private tutor to help them improve their results, what is the likelihood that the change in the sample mean score is less than 10 points? Click the icon to view the table of normal curve areas. Normal Curve Areas P(x< 10) = (Round to three decimal places as needed.) 0. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .0000 .0398 .0793 .1179 .1554 .1915 .0 .1 .0040 .0438 .0080 .0478 .0871 1255 .0160 .0557 .0948 .1331 .1700 2054 .0120 .0517 .0199 .0596 0987 1368 .1736 2088 .0239 .0636 1026 .1406 1772 2123 0279 .0675 1064 1443 1808 2157 .0319 0714 .1103 1480 1844 2190 0359 .0753 1141 1517 1879 2224 .2 .3 .0832 .1217 .1591 1950 .0910 1293 1664 1628 .5 .1985 2019 .2257 .2580 .2881 .3159 3413 2291 2611 .6 .7 .8 .9 1.0 2324 2642 2939 3212 3461 2357 2673 2967…Please help give me correct answerplease put your answers in excel sheet.**** Open the Excel program In our last computer assignment we learned how to find the standard normal distribution up to the given score value a, that is we found P(Z < a). We used Excel instead of the standard normal distribution table and evaluated P(Z<-1.72) with the command =NORMDIST(1.72,B1,B2,TRUE) and we obtained 0.042716 approximately. Here Z is standard normal distribution. In this exercise we will learn how to go backwards, that is from the probability P(Z < a) to the score a. In cell A1 type mean and in cell B1 type 0. That way we are letting mean be zero. Next click on cell A2 and type SD and in cell B2 type 1. That means that we let standard deviation be one. That is, our normal distribution is standard. Suppose we know that the percentile of the score is 4.2716%. We would like to find the corresponding score. Type 0.042716 in B6. That is the given probability of Z<a. We would like to find the…SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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