what can be an analyte for using internal standard? sample: vegetable oil containing ethyl oleate, IS: Ethyl oleate. what should be analyte here (what mixture composions) to use for internal standard method and calibration?

what can be an analyte for using internal standard? sample: vegetable oil containing ethyl oleate, IS: Ethyl oleate. what should be analyte here (what mixture composions) to use for internal standard method and calibration?

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter6: Random Errors In Chemical Analysis

Section: Chapter Questions

Problem 6.15QAP

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Table 1: Volumes in of iodine in mL used to titrate mixtures of 10 mL of reaction mix and 10 mL of urine. student trial 1 trial 2 trial 3 total volume (mL) a 12.6 11.8 12.5 300 290 b. 10.6 10.7 10.6 11.1 118 12. 10.9 405 13.0 12.5 349 mg vit. C mL iodine TV (mL/hour) 10 mL urine aliquot TVC (mg/hour) =7 (mL) · CF !! What is the hourly vitamin C excretion rate (mg/h) of student b if the CF is 1.06? (include no more than two decimals in your answer, e.g.: 123.45, and do not type the units) 10.6 need ASAP
Mass of Sample Volume of KMnO, solution used in titration Equivalents of permanganate used Equivalents of iron (II) in sample Moles of iron (II) in sample Grams of Iron in Sample % Iron in Sample Average % Iron in Unknown Instructor's Grade for Precision in Part B. Sample Calculations Part B: 0.58179 0.68719 28.19 ml 31,96m6 007662 00266 2 11 n
Often the analyst will compare known quantities of analyte to unknown quantities of the material to be analyzed. This may be done in one of three ways: -use calibration curves; use standard additions; or use internal standards. The method of standard additions would be used when A) the quantity of sample analyzed or the instrument response varies from run to run. B) the standard solutions and the unknown solution all have similar characteristics are unaffected by the other material in the sample. C) the sample composition is unknown or complex and affects the analytical signal.
Sheet 5 From the following data determine the following: Define outlier and then identify the outlier in the data. Determine if the outlier should be kept of discarded from the data. Trial 1 2 3 4 HCl (mL) 22.3 28.4 29.8 29.3 NaOH (mL) 35.2 35.1 34.9 35.0
00 mL of a diprotic acid primary standard solution was accurately prepared to a concentration of 0.1431 M. Three samples of this primary standard solution were used as samples in a titration to standardize an aqueous solution of sodium hydroxide, NaOH, which would be used as a titrant. Using the following table of data for the titration of the primary standard acid with NaOH, calculate the average concentration of NaOH. Trial # Volume of primary standard Initial titrant volume Final titrant volume 1 10.00 mL 8.21 mL 27.22 mL 2 10.00 mL 27.22 mL 46.23 mL 3 10.00 mL 30.28 mL 49.29 mL 0.1506 M 0.0753 M 0.0376 M 0.1431 M 0.0526 M
sodium chloride. Dosage form, qualitative and quantitative analysis?
PS. Further values required for the solvings are give in the various situations below. (ANSWER) Situation: A community in a mountainous area of Bohol uses water collected from a nearby natural spring. A sample was submitted to a laboratory for the analysis of its total hardness. Required: SHOW YOUR COMPLETE CALCULATIONS. BASED ON THE IMAGE PROVIDED BELOW FOR THIS QUESTION: Calculate the amount of titrant used in each trial to reach endpoint. Report total hardness of the sample as mean ±sd. a. 250.0 mL of 500.0 ppm of CaCO3 solution from a primary standard (assume solvent is distilled water only). Answer : Mass of CaCO3 = 0.125 g b, The EDTA solution was standardized by titrating it with a 25.0 mL aliquot of the CaCO3 solution. How much of the titrant was consumed. Answer: Volume of EDTA consumed = 12.405 g c. Calculate the average titer (mg CaCO3/mL EDTA). Mass of CaCO3 in 25 mL CaCO3 solution: 0.0125 g Answer: 1.008 mg CaCO3/ mL EDTA
NaOH is the base (please elaborate) Thank you!
Answer the follow up question.
4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.
1. What is the gravimetric factor involved? 2. What is the percentage weight of the analyte in trial 1? 3. What is the percentage weight of the chloride ions in trial 1?
Please provide the correct answers based on the following attached data.