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what assumptions are required for a z-score hypthesis test? A. all of the above B. The score in the

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average American gets a haircut every 43 days. Is the average different for college students? The data below shows the results of a survey of 11 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 32, 46, 49, 45, 50, 49, 43, 45, 38, 46, 42 What can be concluded at the the a =0.01 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Họ: ? Select an answer v H. Select an answer Y C. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value - (Please show your answer to 3 decimal places.) e. The p-value is 2 f. Based on this, we should Select an answer the null hypothesis, g. Thus, the final conclusion is that, The data suggest the populaton mean is significantly different from 43 ata = 0.01, so there is fficient evidence tr conrlide that -he nonulation.
The average income in a certain region in 2013 was $78,000 per person per year. Suppose th standard deviation is $33,000 and the distribution is right-skewed. Suppose we take a random sample of 100 residents of the region. a. Is the sample size large enough to use the Central Limit Theorem for means? Explain. b. What are the mean and standard error of the sampling distribution? c. What is the probability that the sample mean will be more than $3,300 away from the population mean? a. Choose the correct answer below. A. Yes, it is large enough because the sample size of 100 is greater than 25. B. No, it is not large enough because the sample size of 100 is not greater than 10% of the population. OC. Yes, it is large enough because the population standard deviation of 33,000 is larger tha the sample size of 100. OD. No, it is not large enough because the sample size of 100 is less than 250. b. The mean is $ and the standard error is $ (Type integers or decimals. Do not round.) c. The…
4a. Suppose that 35% of senior citizens have a social media account. If we survey 150 senior citizens, what is the mea of the sampling distribution?
The ANOVA procedure is a statistical approach for determining whether or not... the means of more than two populations are not equal the means of more than two samples are not equal the means of more than two populations are equal the means of more than two samples are equal None of the above are true
Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the difference between two population proportions p, and p, at the given level of significance a using the given sample statistics. Assume the sample statistics are from independent random samples. Claim: P1 = P2, a = 0.10 Sample statistics: X1 = 108, n, = 128 and x, = 32, n, = 195 ... Ha: P1 7 P2 O E. Anormal sampling distribution cannot be used, so the claim cannot be tested. Find the critical values. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. A. The critical values are - z, = 1.28 and zo =1.28 (Round to two decimal places as needed.) B. A normal sampling distribution cannot be used, so the claim cannot be tested. Find the standardized test statistic. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. (Round to two decimal places as needed.) Z= B. A normal sampling distribution…
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Resources Civo Up? O Hint Check. A USA Today poll asked a random sample of 1012 U.S. adults what they do with the milk in the bowl after they have eaten the cereal. Let p be the proportion of people in the sample who drink the cereal milk. A spokesman for the dairy industry claims that 70% of all U.S. adults drink the cereal milk. Suppose this claim is true. Verify the sampling distribution of p is approximately Normal. O Because np = 1012(0.70) = 708.4 > 10 and n(1- p) = 1012(0.30) = 303.6 > 10, the sampling distribution of ô is not approximately Normal. O Because p = 0.70, the sampling distribution of p is skewed to the left. O Because np = 1012(0.70) = 708.4 2 10 and n(1- p) = 1012(0.30) = 303.6 > 10, the sampling distribution of p is approximately Normal. Because 1012 > 30, the sampling distribution of p is not approximately Normal. O Because 7o > 30, the sampling distribution of p is approximately Normal. D IMG_0173.jpeg IMG 0174.jpeg Show all 1:00 PM 1/19/2021
In the textbook, a sampling distribution can be regarded as approximately normal when which conditions are met?
You intend to conduct a goodness-of-fit test for a multinomial distribution with 6 categories. You collect data from 53 subjects. What are the degrees of freedom for the x distribution for this test? d.f. = %3D
For the data set given, what is the standard error of the sampling distribution of mean difference scores for n=4. a. .91 b. 2.25 c. 3.33 d. .52
What is the sample test statistic? How do I find P?