What are the maximum and minimum number of rows returned by the R1 right outer join R2? a. Min = rows in R2, max = rows in RI * rows in R2 b. Min = 0, max = rows in R1 + rows in R2 c. Min = 0, max = (rows in R1 + rows in R2) - 1 d. Min = rows in R2, max = (rows in RI + rows in R2) - I
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What are the maximum and minimum number of rows returned by the R1 right outer join R2?
a. Min = rows in R2, max = rows in RI * rows in R2
b. Min = 0, max = rows in R1 + rows in R2
c. Min = 0, max = (rows in R1 + rows in R2) - 1
d. Min = rows in R2, max = (rows in RI + rows in R2) - I
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- What are the maximum and minimum number of rows returned by the RI right outer join R2? a. Min = rows in R2, max = rows in RI * rows in R2 b. Min = 0, max = rows in RI + rows in R2 c. Min = 0, max = (rows in RI + rows in R2) - 1 d. Min = rows in R2, max = (rows in RI + rows in R2) — 1Q4: Table ‘Student’ has 15 rows and table ‘Teacher’ has 20 rows. How many rows will be produced by Cross join of these two tables (Student X Teacher)?In java create an application to manage your data base information the database is already created in mysql tables, the tables are fill, So the user can use your database application user friendly Retrieve all data: Given a table name, retrieve all data from the table and present it to the user. Average: Given a table name and a column name, return the average of the column. Here the assumption is that the column type will be numeric (e.g., cost column). Insert: Given a table name, your program should show the column names of that table and ask the users to input new data to the table. In case of errors, your program should directly show the MySQL errors to the users. Assumption 1: Users will enter data according to the database constraints. Assumption 2: Users will input one record at a time. Delete: Given a table name, your program should show the column names of that table and ask the users to input data that they want to delete. Assumption 1: Users will enter data according to the…
- What are the maximum and minimum number of rows returned by the R1 right outer join R2? a. Min = rows in R2, max = rows in R1 * rows in R2 b. Min = 0, max = rows in R1 + rows in R2 c. Min = 0, max (rows in R1 + rows in R2) - 1 d. Min rows in R2, max = (rows in R1 + rows in R2) – 1 6.Try switching the joins pthread_join(tid2, NULL); pthread_join(tid1, NULL); Do you see any difference? Please report if and why you do or do not see any difference in terms of the randomness in the result of the shared resource. In the inc_dec_resource() function, implement mutual exclusion (pthread_mutex_lock) to ensure that the result becomes 0 every time when you execute your program. Put your updated code in the report (highlighted) and show your screenshot of the execution by running the script three time using $ time ./shared_resource_mutex. Hint: Your loop is incrementing/decrementing the resource which should be protected by each thread while it is executing that portion. /* Compile: gcc -o shared_resouce_mutex shared_resource_mutex.c -lpthread Execute: ./shared_resource_mutex */ #include <stdio.h> #include <pthread.h> #define iterations 300000000 long long shared_resource = 0; pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; // Thread function to…Try switching the joins pthread_join(tid2, NULL); pthread_join(tid1, NULL); Do you see any difference? Please report if and why you do or do not see any difference in terms of the randomness in the result of the shared resource. In the inc_dec_resource() function, implement mutual exclusion (pthread_mutex_lock) to ensure that the result becomes 0 every time when you execute your program. Put your updated code in the report (highlighted) and show your screenshot of the execution by running the script three time using $ time ./shared_resource_mutex. Hint: Your loop is incrementing/decrementing the resource which should be protected by each thread while it is executing that portion. #include <stdio.h> #include <pthread.h> #define iterations 300000000 long long shared_resource = 0; pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; // Thread function to modify shared resource void* inc_dec_resource(void* arg){ //get the pointer from main thread and dereference it…
- Suppose a qüery sumServ sums the quantities in the CustomerBillitem table and a query sumWaste sums the quantities in the FoodWaste table. For the purpose of summing the quantities in sumServ and sumWaste, the following query design needs: sumserv sunWaste Storeio Storeib FoodiD Foodio Sumoruantity SumorQuantity sen wastew 1) No join from servWk to wasteWk 2) A left outer join on FoodiD 31 Left outer joins on StorelD and FoodID 4) All left outer joins2. Get the Groups As new students begin to arrive at college, each receives a unique ID number, 1 to n. Initially, the students do not know one another, and each has a different circle of friends. As the semester progresses, other groups of friends begin to form randomly. There will be three arrays, each aligned by an index. The first array will contain a queryType which will be either Friend or Total. The next two arrays, students1 and students2, will each contain a student ID. If the query type is Friend, the two students become friends. If the query type is Total, report the sum of the sizes of each group of friends for the two students.2- selects the order line items (orderNumber, orderlinenumber) fromthe “orderdetails” table. Also, display the subtotal (quantityOrdered * priceEach) for eachline item and sorts the result set based on the subtotal descending .3- Display unique last names from employees table ordered by last name.4- Display customerNumber, customerName and creditLimit for getting the top five customerswho have the highest creditLimit.5- Find customer Name, customer country, sales representative employee number fromcustomers who do not have a sales representative.6- For each order status, display status and count of orders have this status.7- For Each order number in order details table, Display order number, sum of quantityordered (itemsCount) and sum of (priceEach * quantityOrdered) as total. With condition“total” greater than 1000.8- Display product code, product name and text description for product.9- Find customer number, customer name, order status and order number, for customerwith their orders…
- The Driver Relationship team realized that maintaining driver IDs is difficult and requested an automatic way of incrementing the value when a new driver is added. You need to make the changes on the table to automatically increment the Driver ID. After the change, you need to insert the following driver: First Name: Nursin Last Name: Yilmaz Driving License ID: 4141447 Start Date: 2019-12-28 Driving License Checked: True Rating: 4.0 THIS IS IN SQL FORMAT FOR CENGAGE MINDTAP, PLEASE HELP I AM STUCKAssume that a PriorityQueue has following elements: [20, 30, 50, 40]. What will be its contents after we poll (i.e., remove) one element?> Implements aggregate functions. APPROX_COUNT_DISTINCT Returns the approximate number of rows that contain distinct values of expression. SELECT APPROX_COUNT_DISTINCT(manager_id) AS "Active Managers" FROM employees; Active Managers 18 From the given below URL implements these aggregate functions: AVG COUNT FIRST МАХ MIN STDDEV SUM VARIANCE
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