What are the charge on and the potential difference across each capacitor in (Figure 1) if AV = 11 V? %3D

An air-filled parallel-plate capacitor has an area of 0.001 m² and seperation betweeen the plates is 0.05 mm. The capacitor is connected to a 5 V battery. Eg 8.85 x 10-12 F/m. When the capacitor is fully charged, find capacitance of the capacitor potential difference between the plates electric field between the plates charge on the plates Unit Select an answer O electric field between the plates charge on the plates Unit Select an answer potential energy stored in the capacitor Unit Select an answer C Now, the battery i disconnected and a dielectric medium (dielectric constant = 3) is inserte between the plates. Find capacitance of the capacitor potential difference between the plates microC, Unit Select an answer O microF, Unit Select an answer C potential energy stored in the capacitor V/m, V, mJ.

Figure shows a parallel plate capacitor of plate area A and plate separation d. The gap between plates is filled with materials of dielectric constants K1 = 2, K2 = 1, K3 = 3 and K4 = separations shown on the figure. 6 with area and A a) Find the capacitance in terms of C if C = co4. b) For A = 8cm? and d = 8mm and potential difference V = 100 V applied the plates, find d/2 %3D d ↑d/4 K1 charge on the capacitor plates. K4 K1 d/2 c) Find energy stored between the plates. d/2 A/4 A/4 K2 t/p A/2 A/2

Q3/ A parallel plate capacitor whose plates are (15 cm X 4 cm) and separated by 1 mm air gap and connected to a 24 V battery (ɛ,=8.85x1012 C²/N.m². Calculate the followings; 1- The capacitance of the capacitor. 2- The charge on each plate. 3- The electric field across the capacitor. 4- The energy stored in the capacitor. 5- If a slab of paper with dielectric constant K=3.25 is inserted between the plates, Find the new value of charge on each plate.