Weekly demand for a certain brand of a golf ball at The Golf Outlet is normally distributed with a mean of 35 and a standard deviation of 5. The profit per box is $5.00. Write an Excel formula that simulates the weekly profit: O 5 RANDBETWEEN(5, 35) O 5 35 NORMSINV(RAND()) ONORMINV(RAND(), 5.35, 5) O=5° NORMINV(RAND(), 35, 5)

Weekly demand for a certain brand of a golf ball at The Golf Outlet is normally distributed with a mean of 35 and a standard deviation of 5. The profit per box is $5.00. Write an Excel formula that simulates the weekly profit: O 5 RANDBETWEEN(5, 35) O 5 35 NORMSINV(RAND()) ONORMINV(RAND(), 5.35, 5) O=5° NORMINV(RAND(), 35, 5)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Biological oxygen demand (BOD) is a pollution index that is monitored in the treated effluent of paper mills. A certain paper mill has taken 31 samples over the past 3 months. The mean and standard deviation for the sample data are 3.42 and 0.728 ppm respectively. The mill would like to see if this sample indicates that the true average BOD in their treated effluent exceeds the targeted 3.00 ppm. Let ? = 0.05. A) The test statistic, (ttest), for this data set is: Note: Round your answer to the nearest hundredth.B) The p-value is: C) The statistical decision and corresponding English interpretation for this study are: Fail to reject Ha: conclude that the true BOD in treated effluent exceeds 3 ppmFail to reject Ho: we cannot conclude that the true BOD in treated effluent exceeds 3 ppm Reject Ha: we cannot conclude that the true BOD in treated effluent exceeds 3 ppmReject Ho: conclude that the true BOD in treated effluent exceeds 3 ppm
A professor believes the students in a statistics class this term are more creative than most other students attending the university. A previous study found that students at the university had a mean score of 35 on a standard creativity test, and the current class has an average score of 40 on this scale with an estimated population standard deviation of 7. The standard deviation of the distribution of means is 1.63. The t score is (40 – 35) / 7 = 0.71 (40 – 35) / 1.63 = 3.07 (40 – 35) / 72 = 5 / 49 = 0.10 (40 – 35) / 1.632 = 5 / 2.66 = 1.88
Suppose that the hemoglobin levels among healthy females are normally distributed with a mean of 14.1 gdL. Research shows that exactly 95% of healthy females have a hemogoblin level of 16.1 gdL. What is the standard deviation of the distribution of hemoglobin levels and healthy females. Carry you intermediate computations to atleast four decimal places, and round your answer to at least two decimal places.
From the following data calculate (i) Correlation coefficient (ü) Standard Deviation of Y (Gy) X=-85 Y Y= 89 X Gz=3
The mean score on a driving exam for a group of driver's education students is 60 points, with a standard deviation of 3 points. Apply Chebychev's Theorem to the data using k=2. Interpret the results. At least ( )% of the exam scores fall between ( )and ( )
If the power received at the MU is lognormal with standard deviation of 9dB, the outage probability can be expressed as erfc(x)/2. determine the value of x given the average power received is -97dBm and the threshold power is -101dBm.
An analyst for a transportation metro is asked to examine the time required (x) in minutes for a specific commute route. She records 200 randomly sampled times and finds: Σx = 11,000 and Sxx =1791. Find the average commute time, as well as standard deviation and coefficient of variation.
stion 16: nts) A random sample of 200 psychology students was selected from a department's participant pool. A researchers determined each student's score on the NPI-16 and the number of his or her Facebook friends. The marginal distribution of NPI-16 scores was 4, with a standard deviation of 2. The marginal distribution "Facebook Friends" was 450, with a standard deviation of 200. The correlation between the two variables was .15. Assuming that NPI-16 is the predictor variable and Number of Facebook Friends is the outcome variable, compute the following: The lower limit of the 95% confidence interval around b. Note: Enter your answer to the second decimal place.
A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1025 h with a standard deviation of 83 h.Find the z-scores for lightbulbs which last 850 and 900 h. (Round your answers to two decimal places.) 850 h: z = 900 h: z =
The coefficients of variations of wages of male workers and female workers are 55% and 70% respectively, while the standard deviations are 22.0 and 15.4 respectively calculate the overall wages of all workers given that 80% of the workers are male?
=90, perform a two-tailed t test witha-05 = 81.19 and Given lo % based on a sample of N= 4 scores with a mean of X s = 6.89.