We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 276 had kids. Based on this, construct a 95% confidence interval for the proportion, p, of adult residents who are parents in this county. Give your answers as decimals, to three places.

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

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Q: I've asked 91 students on Monday whether they did their homework over the weekend. 20 of them said…

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Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: just answer the following mcqs

A: 1.The difference between two population proportions may give result in following options…

Q: Out of 400 people sampled, 344 had kids. Based on this, construct a 99% confidence interval for the…

A: Given that sample size n = 400 Number of peoples with kids, X = 344 The critical value of Z at 99%…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A:

Q: Out of 300 people sampled, 138 had kids. Based on this, construct a 90% confidence interval for the…

A: Given data, n=300 x=138 p=x/n=138/300 =0.46 z-value at 90% confidence is Zc=1.645

Q: We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 500…

A: The sample proportion of the sample of size n can be defined as:  Here, X = Total number of success…

Q: Out of 600 people sampled, 552 had kids. Based on this, construct a 90% confidence interval for the…

A: In statistical inference, there are two types of estimation,  Point estimation and Interval…

Q: Out of 600 people sampled, 486 had kids. Based on this, construct a 95% confidence interval for the…

A: It is given that  Favourable cases, X = 486 Sample size, n = 600

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

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Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

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Q: Out of 500 people sampled, 190 had kids. Based on this, construct a 90% confidence interval for the…

A: Given : Sample Size, n = 500 Number of successes, x = 190 confidence level,c=0.9

Q: Out of 400 people sampled, 68 had kids. Based on this, construct a 99% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the number of people sampled. From the…

Q: Out of 300 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

A: Introduction Sample size, n=300 No. of people who had kids, x=228 CL=0.90

Q: In a survey of 323 adults over 50, 60% said they were taking vitamin supplements. Find the margin of…

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Q: x=111, n=194, Confidence level = 99%

A: The sample proportion of p is, p^=xn=111194=0.5722 Computation of critical value:…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Obtain the 95% confidence interval for the true proportion of adult residents who are parents in…

Q: Out of 500 people sampled, 455 had kids. Based on this, construct a 90 % confidence interval for the…

A: The formula for the confidence interval for the proportion is,

Q: In a sample of 530 adults, 445 had children. Construct a 99% confidence interval for the true…

A: We have given that,  Favorable cases (X) = 445 and sample size (n)=530 Then,  We will find the 99%…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: Out of 200 people sampled, 10 had kids. Based on this, construct a 95% confidence interval for the…

A: Sample size Out of which  had kids.The objective is to construct  95% confidence interval for the…

Q: If n = 15, the sample mean = 150, SD = 10, what is the confidence interval (using 99% confidence…

A: Given data,n=15x=150σ=10z-value at 99% confidence is Zc=2.576

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Solution

Q: Convert the estimate and your confidence interval to Percents. Discuss reasons the estimate might be…

A: We have to convert the estimate and confidence interval into the percentage.

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

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Q: Rosetta wants to estimate the percentage of people who rent their home. She surveys 250 individuals…

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Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: 980 adults to learn about their gym membership. The results showed that 574 of the respondents lack…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…

Q: Out of 400 people sampled, 220 had kids. Based on this, construct a 99% confidence interval for the…

A: The random variable X follows binomial distribution. X ~ B (n, p) The sample size is 400. The number…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Solution: Let X be the number of parents had kids and n be the sample number of adults. From the…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: A sample of 600 adult residents sampled, 426 had kids. That is, x=426,n=600. The sample proportion…

Q: A national polling organization surveyed 1000 Americans and found that 350 admitted to being guilty…

A: Given values, n = 1000 x = 350 Significance level = 0.10 Calculate z

Q: If n=550 and X = 440, construct a 90% confidence interval. Give your answers to three decimals <p<

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Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: as per our company guidelines we are supposed to answer only first question. Kindly repost other…

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: and X = 96, construct a 90% confidence interval for the population proportion, p. Give your answers…

A: Given X=96 N=120

Q: Out of 500 people sampled, 145 received flu vaccinations this year. Based on this, construct a 90%…

A: We have given that  Sample size n=500 , favorable cases x=145 90% confidence interval  Sample…

Q: you want to find out the percent of people who use an iPhone so you survey 120 random adults of whom…

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Q: Out of 600 people sampled,  510 had kids. Based on this, construct a 90% confidence interval for the…

A: It is given that Out of 600 people sampled,  510 had kids.

Q: In a sample of 570 adults, 485 had children. Construct a 95% confidence interval for the true…

A: The sample size is 570. The number of successes is 485. We have to construct 95% confidence interval…

Q: In recent survey of 1092 students, 966 of them would like to recommend www.helpyourmath.com to their…

A: Given;n = 1092x = 966confidence level 95%