We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 276 had kids. Based on this, construct a 95% confidence interval for the proportion, p, of adult residents who are parents in this county. Give your answers as decimals, to three places.

Q: I've asked 91 students on Monday whether they did their homework over the weekend. 20 of them said…

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Q: í 600 people sampled, 348 had kids.

A: Given that  Sample size (n) = 600 Had kids (X) = 348   We know that  Best point estimate (p)= xn…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: just answer the following mcqs

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Q: A national polling organization surveyed 1000 Americans and found that 350 admitted to being guilty…

A: Given: x=350 n=1000 p^=xn=3501000=0.35

Q: Out of 400 people sampled, 232 had kids. Based on this, construct a 95% confidence interval for the…

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Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A:

Q: A poll of 1060 adults in a country was conducted by telephone. Of those surveyed, 169 had…

A: The sample size is 1060 and number of success is 169.

Q: The confidence interval for a population porportion is (0.34, 0.5). What the the sample proportion…

A: Given  The confidence interval for a population proportion (0.34,0.5)  estimate the sample…

Q: Out of 600 people sampled, 486 had kids. Based on this, construct a 95% confidence interval for the…

A: It is given that  Favourable cases, X = 486 Sample size, n = 600

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

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Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Solution: It is given here:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

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Q: Out of 500 people sampled, 190 had kids. Based on this, construct a 90% confidence interval for the…

A: Given : Sample Size, n = 500 Number of successes, x = 190 confidence level,c=0.9

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A: Given X=25 n=500 95% confidence interval

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Q: In a random sample of 500 adults, 410 described themselves as vegetarians. Construct a 95%…

A: We have been provided with the following information about the adults who describe themselves as…

Q: x=111, n=194, Confidence level = 99%

A: The sample proportion of p is, p^=xn=111194=0.5722 Computation of critical value:…

Q: What time period does graph 4 include?

A: Note: Hey there! Thank you for the question. As you have specifically mentioned the question 13, it…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Obtain the 95% confidence interval for the true proportion of adult residents who are parents in…

Q: Out of 500 people sampled, 455 had kids. Based on this, construct a 90 % confidence interval for the…

A: The formula for the confidence interval for the proportion is,

Q: aOf 500 random people surveyed, 72 were smokers. Find the 80% confidence interval for smokers.

A: It is given that, Out of 500 random people surveyed, 72 were smokers. So, the portion of the…

Q: lculating the confidence interval.

A: x Freq 1 3 2 5 3 19 4 7 5 6 Total 40

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A: The sample size is 1072, 67% say they are willing to get a second or part-time job to pay for their…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Solution

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A: From the provided information,

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A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…

Q: Out of 500 people sampled, 330 had kids. Based on this, construct a 90% confidence interval for the…

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Q: 980 adults to learn about their gym membership. The results showed that 574 of the respondents lack…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…

Q: A marketing study by Ford Motor Company finds that 320 of the 650 buyers of compact cars were women.…

A: Let the population proportion of women who bought compact cars be P Given:         Sample size n =…

Q: Out of 400 people sampled, 220 had kids. Based on this, construct a 99% confidence interval for the…

A: The random variable X follows binomial distribution. X ~ B (n, p) The sample size is 400. The number…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Solution: Let X be the number of parents had kids and n be the sample number of adults. From the…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: A sample of 600 adult residents sampled, 426 had kids. That is, x=426,n=600. The sample proportion…

Q: A national polling organization surveyed 1000 Americans and found that 350 admitted to being guilty…

A: Given values, n = 1000 x = 350 Significance level = 0.10 Calculate z

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: Given,Sample size(n)=100no.of parents(X)=15

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Q: In one city, 27.8% of the 9000 students surveyed said they eat at the school cafeteria. Find the 95%…

A: To find the 95% confidence interval for the proportion of students who said they eat at the school…