We want to find the magnetic field at the center of a circular current loop shown below. The magnetic field due to the small segment ds of the ring is dB = ||d|| HoI ||dsxf|| HI ds sino R p2 What is the angle o in the expression above? de R 90 – 0 90° zero O o o O
Ampere Circuital Law
Ampere's Law states that "for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.”
Current Density
To design the electrical and electronic system, the current density is an important factor. The designer current level is the factor on which the circuit performance depends and with the help of the dimensions of the conducting current the current density is then determined. For instance, despite the lower current demanded by smaller devices as integrated circuits are reduced in size, there is a type of trend in achieving the higher device number in even smaller chip areas. The current density is increased in this region at higher frequencies because the conducting region in a wire becomes confined and this is known as the skin effect. The consequences increase as the current densities become higher.
![We want to find the magnetic field at the center of a circular current loop shown below. The magnetic field
due to the small segment ds of the ring is
|| 4xsp|| I°r1
R?
HI ds sino
dB = ||d||
p2
What is the angle ø in the expression above?
de
R
90 – 0
90°
zero](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0335de1d-d88b-4764-a43c-e2195c6bbbda%2Fa2ed1a2c-cda5-4723-b2de-e03396aea97a%2F0yfco6e_processed.png&w=3840&q=75)
![Integrating the the Biot Savart law over the circular loop of radius R (shown in the problem above) gives the
magnetic field at the center of the ring.
What is the magnetic field at the center of the ring?
O HI
out of the page
2nR
O HoI
-out of the page
2R
O HoI
into the page
2TR
zero
HọI
into the page
2R](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0335de1d-d88b-4764-a43c-e2195c6bbbda%2Fa2ed1a2c-cda5-4723-b2de-e03396aea97a%2F43dze9_processed.png&w=3840&q=75)
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