We have the language where {a,b} is the set of terminal symbols. Which set of production rules for G with start symbol S (a nonterminal) can generate it? (assuming all symbols involved other than the terminal symbols are in the alphabet as nonterminal symbols.) O O L(G) = {aa"ba" aln € Z,n >0}, DO SaAa, AaAa, A → b S→ baSba, S→ b SaAa, A→ bA, A → b SbaSab, S→b

We have the language where {a,b} is the set of terminal symbols. Which set of production rules for G with start symbol S (a nonterminal) can generate it? (assuming all symbols involved other than the terminal symbols are in the alphabet as nonterminal symbols.) O O L(G) = {aa"ba" aln € Z,n >0}, DO SaAa, AaAa, A → b S→ baSba, S→ b SaAa, A→ bA, A → b SbaSab, S→b

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

question in image
Topic: Pumping Lemma
2. Let RE be the set of regular expressions over alphabet E = {0, 1}, and for r E RE, let L(r) be the language denoted by r. Consider the claim: VL E P(E*),Vr1, r2 E RE, (|L(r1)| > 1 A L \ L(r2) = L(r1)) = L is regular Either prove this, or find L, rı and r2 that provide a counter-example.
Give a DFA M that accepts the language L2 = {w | w ∈ {a, b} ∗ and w 6∈ {b ia j |i, j > 0 }}..
Please help me with this, I'm stuck...
Prove that L = {w € {a, b, c, d}* | #.!-) = #6(w) = #c(w) = #a(w)} is not context-free. (Hint: No need to apply pumping lemma here.)
Can you please help me with question 2.7 part B because I am struggling with this problem that I just don't understand. Can you please do a state diagram for the push down automaton for part B. question for 2.7 2.7 Give informal English descriptions of PDAs for the language. B. The complement of the language {a^n b^n | n ≥ 0}
Let regular language L1 recognized by DFA (Q1,Z,81,s1,F1) and regular language L2 recognized by DFA (Q2,1,82,s2,F2). We will construct a product DFA as the quintuple (Q,E,8,s,F) where: •Q=Q1×Q2 •For allxeZ and (q1,q2)EQ1×Q2,8((q1,q2),x) = (81(q1,x),82(q2,x)) •s= (s1,s2) Suppose we have a DFA that recognizes concatenation of two languages L1 L2. Also suppose we have a DFA that recognizes L2. Using these two DFAS, can we construct a new DFA to recognize L1? If yes, construct it.lf no, explain why. Let regular language L1 recognized by DFA (Q1,E,81,s1,F1) and regular language L2 recognized by DFA (Q2,1,82,s2,F2). We will construct a product DFA as the quintuple (Q,E,8,s,F) where: •Q=Q1×Q2 •For allxeE and (q1,q2)EQ1×Q2,8((q1,q2),x) = (81(q1,x),82(q2,x)) •s= (s1,s2) Suppose we have a DFA that recognizes concatenation of two languages L1 L2. Also suppose we have a DFA that recognizes L2. Using these two DFAS, can we construct a new DFA to recognize L1? If yes, construct it.If no, explain…
2. Let RE be the set of regular expressions over alphabet E = {0, 1}, and for r E RB, let L(r) be the language denoted byr. Consider the claim: VL E P(E"), Vri,ra € RE, (C(r1)) > 1AL\ C(r) = C(ri)) L is regular Either prove this, or find L,ri and ra that provide a counter-example.
Are the functions one to one or onto only? I. f : N → Z : x ↔ x II. f : N → N : x ↔ x III. f : Z → N ∪ {0} : x ↔ |x|
2. Consider the following language: {r € {a,b}* | #a(x) < 2#b(x)} (a) Give a CFG for this set. (b) Prove that the given CFG is correct.
Use the Pumping Lemma to show that the the following language over {a,b,c}* is not CF {wct | t ∈ {a,b}* ∧ w is a substring of t}