We have a list of three dimensional points [(7, 8, 1).(3, 7, 5).(6, 4, 1).(6, 9, 5).(0, 5, 2).(9, 9, 0)]. We sort these in ascending order by the third coordinate. Which of the following corresponds to a stable sort of this input?

Pick one million sets of 12 uniform random numbers between 0 and 1. Sum up the 12 numbers in each set. Make a histogram with these one million sums, picking some reasonable binning. You will find that the mean is (obviously?) 12 times 0.5 = 6. Perhaps more surprising, you will find that the distribution of these sums looks very much Gaussian (a "Bell Curve"). This is an example of the "Central Limit Theorem", which says that the distribution of the sum of many random variables approaches the Gaussian distribution even when the individual variables are not gaussianly distributed. mean Superimpose on the histogram an appropriately normalized Gaussian distribution of 6 and standard deviation o = 1. (Look at the solutions from the week 5 discussion session for some help, if you need it). You will find that this Gaussian works pretty well. Not for credit but for thinking: why o = 1 in this case? (An explanation will come once the solutions are posted).

I am trying to work with some generic search algorithms in a coding homework, and I am having trouble understanding some of it. Here are my questions:   1. For this linear search algorithm below I am trying to send an array of x and y cordinate points into it and search to see if a specific x, y point is in the array, but I don't know how to send the points into the linear search function. By the way, I am using a struct point type for the array of points and the point I am looking for. (The below code is an exact example from our teacher during a lecture.)   void* linearSearchG(void* key, void* arr, int size, int elemSize, int(*compare)(void* a, void* b)) {   for (int i = 0; i < size; i++) {   void* elementAddress = (char*)arr + i * elemSize; if (compare(elementAddress, key) == 0) return elementAddress; } return NULL; }     2. I forgot what this line of code specifically does: void* elementAddress = (char*)arr + i * elemSize;   I need to code this myself, so if you could explain…

Consider a set of random numbers IIDR [0,1] = [0.11,0.63,0.37,0.08,0.71,0.56,0.45,0.29,0.68]. Convert the set of random number to a set of random variates for N(0,1). Further convert this set of random variates to another set for N(5,3). Present the random numbers and the random variates in a Table as sought below. S.no IIDR[0,1] Random Variates for N(0,1) Random Variates for N(5,3)