We can show that the series 1 2" – n n=1 Σ is convergent by applying the limit comparison test with the convergent geometric series 1 Σ 2" n=1 What is the value of the limit 1/(2" – n) lim 1/2" n→00 that we need to compute to apply the test?

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A: We will use standard formula of known power series expansion

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A: Differentiation

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A: To find that the series converges or diverges.

Q: Use the Limit Comparison Test to determine the convergence or divergence of the series.

A: Limit comparison test: Suppose we have two series ∑an and ∑bn . Define limn→∞anbn=L If L is positive…

Q: Suppose that Cnxn converges when x = -4 and diverges when x = 6. What can be said about the…

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Q: Use the Limit Comparison Test to determine the convergence or divergence of the series. + 8) n= 1…

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