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wave functions for two waves traveling on a string are described by: y1 (x, t) = A sin (3nx- 40nt) y2 (x, t) = A sin (3nx + 40nt) and %3D where, y and x are in meters, and t is in seconds. An element of the string oscillating vertically with amplitude A would be located at: O x = (1/12) m O x = (1/15) m O x = (1/18) m O x = (1/8) m Y = (1/6) m

wave functions for two waves traveling on a string are described by: y1 (x, t) = A sin (3nx- 40nt) y2 (x, t) = A sin (3nx + 40nt) and %3D where, y and x are in meters, and t is in seconds. An element of the string oscillating vertically with amplitude A would be located at: O x = (1/12) m O x = (1/15) m O x = (1/18) m O x = (1/8) m Y = (1/6) m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The wave functions for two waves traveling on a string are described by: y(x, t) A sin (3nx and where, y and x are in meters, and t is in seconds. An element of the string oscillating vertically y2(x,t) A sin (3Tx + 40nt) with amplitude A would be located at: x (1/12) m x = (1/15) m O x = (1/18) m Ox- (1/8) m ) x = (1/6) m ifferent media of the figure shown below
Transcribed Image Text:The wave functions for two waves traveling on a string are described by: y(x, t) A sin (3nx and where, y and x are in meters, and t is in seconds. An element of the string oscillating vertically y2(x,t) A sin (3Tx + 40nt) with amplitude A would be located at: x (1/12) m x = (1/15) m O x = (1/18) m Ox- (1/8) m ) x = (1/6) m ifferent media of the figure shown below
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