Water with a velocity of 5.08 m/s flows through a 108 mm diameter pipe. Solve for the volume flow rate in m3/s. Express your answer in 3 decimal places.  pls answer fast thankss

A fluid flow is defined by (6x² − 3y²) m/s and U = - V = (4xy + y) m/s, where x and y are in meters. Part A Determine the magnitude of the velocity of a particle at point (1.9 m, 2 m). Express your answer to three significant figures and include the appropriate units. V μÅ Value m/s Submit Request Answer C ? Part B Determine the magnitude of the acceleration of a particle at point (1.9 m, 2 m). Express your answer to three significant figures and include the appropriate units. a = O μÅ Value 2 m/s² Submit Request Answer ?

PLEASE ANSWER QUESTION #1 ONLY, DISREGARD THE OTHER PROBLEMS GIVEN. SHOW COMPLETE SOLUTION. THANK YOU.   An 8 ft diameter by 16 ft height vertical tank is receiving water (? = 62.5 lb/ft3) at the rate of 295 gal/min and discharging through a 4-in ID line with a constant speed of 6 fps. At a given instant, the tank is half full.   Determine the following:    QUESTION #1: What is the mass change in the tank? note: round off to 2 decimal place   QUESTION #2: What is the water level in the tank 15 min. later? note: round off to 2 decimal place   QUESTION #3: What is the volume change in the tank? note: round off to 2 decimal place

In the network given in the figure, the flow rate of the current passing through the BE pipe is how many (liters/Second)LT/s. Other data for the network are given in the table. K values given in the table, K = fL / (29DA2) using the formula and length size in meters, Time size in seconds have been calculated. Qc QE QB K KCD KDE KDF KBe (LT / S) (LT/S) (LT/S) 2000 2500 2000 3000 3000 600 100 200 Kcd KOF -bile Koe Кве